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Grace [21]
2 years ago
10

The regular price of an item at a store is p dollars.The item is on sale for 20% off the regular price.Some of the expressions s

hown below represent the sale price,i in dollars,of the item
Mathematics
1 answer:
Sergio [31]2 years ago
5 0

Answer: The required expression would be 0.8p.

Step-by-step explanation:

Since we have given that

Let the regular price of an item be 'p' dollars.

Discount % = 20%

So, Amount of discount would be

\dfrac{20}{100}\times p\\\\=0.2p

So, the expression represents the sale price would be

p-0.2p\\\\=0.8p

Hence, the required expression would be 0.8p.

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Javier uses 1/8 teaspoons of nutmeg for each loaf of banana bread he makes. How many loaves of banana bread can javier make with
Reil [10]
If you have 1/8 in every loaf and 1 teaspoon of nutmeg is 8/8 and you have 4 of those think how much is 8/8 x 4.
8 0
1 year ago
Read 2 more answers
The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Nataliya [291]

Answer:

(a) Probability that a sheet selected at random from the population is between 30.25 and 30.65 inches long = 0.15716

(b) Probability that a standard normal random variable will be between .3 and 3.2 = 0.3814

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with;

    Mean, \mu = 30.05 inches        and    Standard deviation, \sigma = 0.2 inches

Let X = A sheet selected at random from the population

Here, the standard normal formula is ;

                  Z = \frac{X - \mu}{\sigma} ~ N(0,1)

(a) <em>The Probability that a sheet selected at random from the population is between 30.25 and 30.65 inches long = P(30.25 < X < 30.65) </em>

P(30.25 < X < 30.65) = P(X < 30.65) - P(X <= 30.25)

P(X < 30.65) = P(\frac{X - \mu}{\sigma} < \frac{30.65 - 30.05}{0.2} ) = P(Z < 3) = 1 - P(Z >= 3) = 1 - 0.001425

                                                                                                = 0.9985

P(X <= 30.25) = P( \frac{X - \mu}{\sigma} <= \frac{30.25 - 30.05}{0.2} ) = P(Z <= 1) = 0.84134

Therefore, P(30.25 < X < 30.65) = 0.9985 - 0.84134 = 0.15716 .

(b)<em> Let Y = Standard Normal Variable is given by N(0,1) </em>

<em> Which means mean of Y = 0 and standard deviation of Y = 1</em>

So, Probability that a standard normal random variable will be between 0.3 and 3.2 = P(0.3 < Y < 3.2) = P(Y < 3.2) - P(Y <= 0.3)

 P(Y < 3.2) = P(\frac{Y - \mu}{\sigma} < \frac{3.2 - 0}{1} ) = P(Z < 3.2) = 1 - P(Z >= 3.2) = 1 - 0.000688

                                                                                           = 0.99931

 P(Y <= 0.3) = P(\frac{Y - \mu}{\sigma} <= \frac{0.3 - 0}{1} ) = P(Z <= 0.3) = 0.61791

Therefore, P(0.3 < Y < 3.2) = 0.99931 - 0.61791 = 0.3814 .

 

3 0
2 years ago
Joey wants to build a rectangular garden. He plans to use a side of a river for one side of the garden, he will not place fencin
jonny [76]

We let x and y be the measures of the sides of the rectangular garden. The perimeter subtracted with the other side should be equal to 92.

<span>                                                       2x + y = 92</span>

The value of y in terms of x is equal to,

<span>                                            y = 92 – 2x</span>

The area is the product of the two sides,

<span>                                                                        A = xy</span>

Substituting,

<span>                                                            A = x (92 – 2x) = 92x – 2x2</span>

Solving for the derivative and equating to zero,

<span>                                                            0 = 92 – 4x  ; x = 23</span>

Therefore, the area of the garden is,

<span>                                                            A = 23(92 – 2(23)) = 1058 yard<span>2</span></span>

4 0
2 years ago
Read 2 more answers
In 2014, 85 percent of households in the United States had a computer. For a randomly selected sample of 200 households in 2014,
DochEvi [55]

Answer:

The mean of C is 170 households

The standard deviation of C, is approximately 5 households

Step-by-step explanation:

The given parameters are;

The percentage of households in the United States that had a computer in 2014 = 85%

The size of the randomly selected sample in 2014, n = 200

The random variable representing the number of households that had a computer = C

Therefore, we have;

The probability of a household having a computer P = 85/100 = 0.85

Let

Therefore;

The mean (expected) number in the sample, μₓ, = E(x) = n × P is given as follows;

μₓ = 200 × 0.85 = 170

The mean of C = μₓ = 170

The variance, σ² = n × P × (1 - P) = 200 × 0.85 × (1 - 0.85) = 25.5

Therefore;

The standard deviation, σ = √(σ²) = √(25.5) ≈ 5.05

The standard deviation of C, σ ≈ 5 households (we round (down) to the nearest whole number)

7 0
2 years ago
Read 2 more answers
In 2001, a total of 15,555 homicide deaths occurred among males and 4,753 homicide deaths occurred among females. The estimated
deff fn [24]

Answer:

a. 11

b. 3

c. homicide mortality rate

d. 11:3

Step-by-step explanation:

a.) If 15,555 homicide cases were recorded among males of 139,813,000 population, then in every 100,000 males, the number of homicides cases will become:

= [15,555/139,813,000] * 100,000

= 11.13 aproximately 11 homicide cases in every 100,000 males.

b.) If 4,753 homicide cases were recorded among Females of 144,984,000 population, then in every 100,000 Females, the number of homicides cases will become:

= [4753/144,984,000] * 100,000

= 3.28 approximately 3 homicide cases in every 100,000 females

C.) Homicide-mortality rate

d.) ratio of male to female homicide rate = 11 : 3

e.) What those rates means is that in every 100,000

Males in 2001, 11 of them were Victims of homicide and in every 100,000 females, 3 of them are victims of homicide.

6 0
2 years ago
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