Work out the length of AB.<br> Give your answer to 3 significant figures.<br> A=(-1,6) B=(5,3)

Jerry makes $40,000 a year working at a nearby factory. He gets two weeks paid vacation per year, plus five other paid holidays.

JulijaS [17]

Answer:

Vacation pays are not included in salaries. Therefore, Jerry's calculation is wrong.

Step-by-step explanation:

Given is :

Jerry makes $40,000 a year working at a nearby factory.

He gets two weeks paid vacation per year, plus five other paid holidays.

So total paid holidays become = $14+5=19$ days

Subtracting 19 from 365 days and assuming that Jerry works for 365 days a year.

We get = $365-19=346$ days

So, his per day salary will be = $\frac{40000}{346}= 115.60$

Vacation pays are not included in salaries. Therefore, Jerry's calculation is wrong.

4 0

1 year ago

Read 2 more answers

During the 2008-2009 financial crisis, the GDP of the USA reduced from $14.72 trillion in 2008 to$14.42 trillion in 2009. What i

Bad White [126]

Answer:

2.04

Step-by-step explanation:

The GDP of USA IN 2008 = $14.72 trillion

The GDP of USA IN 2009 = $14.42 trillion

Change in GDP

$14.72 trillion- $14.42 trillion = $0.3 trillion

Percentage Change

($0.3 trillion/$14.72 trillion) x 100%

0.02038 X 100% = 2.038=2.04 approximately

4 0

2 years ago

One division of a large defense contractor manufactures telecommunication equipment for the military. This division reports that

Zielflug [23.3K]

Answer:

At the 95% confidence level, management should not conclude that the percentage of rework for electrical components is lower than the rate of 12% for non-electrical components, since the upper bound of the confidene interval, which is 0.1339, is higher than 0.12.

Step-by-step explanation:

To reach a conclusion, we have to observe the confidence interval.

Should management conclude that the percentage of rework for electrical components is lower than the rate of 12% for non-electrical components?

Is the upper bound of the confidence interval lower than 12% = 0.12?

If yes, it should conclude that this percentage is lower.

Otherwise, it cannot conclude.

Confidence interval:

0.0758 to 0.1339

0.1339 is higher than 0.12.

So.

At the 95% confidence level, management should not conclude that the percentage of rework for electrical components is lower than the rate of 12% for non-electrical components, since the upper bound of the confidene interval, which is 0.1339, is higher than 0.12.

6 0

1 year ago

Read 2 more answers

Find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Let x, y, and z be the dimensions of the box

Gala2k [10]

Answer:

The dimensions of the box are 12 cm , 12 cm , 12 cm

Step-by-step explanation:

Let x , y and z be the dimensions of box

Volume of box =xyz=1728

$z=\frac{1728}{xy}$

Surface area of box = $2xy+2yz+2xz=2xy+2y(\frac{1728}{xy})+2x(\frac{1728}{xy})$

Let $f(x,y)=2xy+2(\frac{1728}{x})+2(\frac{1728}{y})$

To get minimal surface area

$\frac{\partial f}{\partial x}=0$ and $\frac{\partial f}{\partial y}=0$

$\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial x}=0$

$2y-2(\frac{1728}{x^2})=0$

$y=\frac{1728}{x^2}$ ----1

$\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial y}=0$

$2x-2(\frac{1728}{y^2})=0\\x=\frac{1728}{y^2} \\y^2=\frac{1728}{x}$

Using 1

$(\frac{1728}{x^2} )^2=\frac{1728}{x}$

x=0 and $x^3=1728$

Side can never be 0

So, $x^3=1728$

x=12

$y=\frac{1728}{x^2} \\y=\frac{1728}{12^2}$

y=12

$z=\frac{1728}{xy}\\z=\frac{1728}{(12)(12)}$

z=12

The dimensions of the box are 12 cm , 12 cm , 12 cm

5 0

1 year ago

Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A

MAVERICK [17]

Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
= -2cos4A*sin3A + 2cos4A*sinA
= 2cos4A(sinA - sin3A)
= 2cos4A*2cos(2A)sin(-A)
= -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
= 2cos4A*cos3A - 2cos4A*cosA
= 2cos4A(cos3A - cosA)
= 2cos4A*(-2)sin2A*sinA
= -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
= cos2A/sin2A
= cot2A

This verifies the identity.

4 0

1 year ago

Work out the length of AB. Give your answer to 3 significant figures. A=(-1,6) B=(5,3)