Answer:
Area of ΔABF = 6 square units
Step-by-step explanation:
Answer:
represent the random sample selected
represent the number of pots that were bare ground (no vegetation
And replacing we got:
So then the sample proportion of bare ground spots is 0.792 for this sample
Step-by-step explanation:
We have the following info given from the problem:
represent the random sample selected
represent the number of pots that were bare ground (no vegetation)
And for this case if we want to find the sample proportion of bare ground spots we can use this formula:
And replacing we got:
So then the sample proportion of bare ground spots is 0.792 for this sample
The probability of the first event happening is 1/10 or 0.1
If Ann puts the ball back, there are still 10 balls of which, Ann removed 1. Therefore the probability of the second event is also 0.1.
0.1x0.1=0.01, which is the probability that both women removed the same ball
For this case, the first thing we are going to do is rewrite the expression.
We have then:
(18) / root (8)
(18) / root (2 * 4)
(18) / 2 * root (2)
(9) / root (2)
Thus, the values of a and b are:
a = 9
b = 2
Answer:
a = 9
b = 2
What values of b satisfy 3(2b+3)^2 = 36
we have
3(2b+3)^2 = 36
Divide both sides by 3
(2b+3)^2 = 12
take the square root of both sides
( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3
b1=\frac{\sqrt{12}}{2} -\frac{3}{2}
b1=\sqrt{3} -\frac{3}{2}
b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
therefore
the answer is
the values of b are
b1=\sqrt{3} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
