Question

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 40' Building Als 120 feet away, and building B is 60 feet away which building is taller and by approximately how many feet?
Building A It is around 100 69 feet taller than building B
Building A it is around 50 34 feet taller than building B
O Building B, it is around 100.69 feet taller than building A
Building B, it is around 50.34 feet taller than building A

Answer 1

Answer:

A. Building A, it is around 100.69 feet taller than building B.

Step-by-step explanation:

Since building A is 120 feet away at and elevation of $40^{0}$, then:

Tan $40^{0}$ = $\frac{x}{120}$

Where x is the height of the building at the horizontal plane.

x = Tan  $40^{0}$ × 120

   = 100.692 feet

For building B at the same elevation,

Tan  $40^{0}$ = $\frac{x}{60}$

 x = Tan  $40^{0}$ × 60

    = 50.346 feet

Since the angle of elevation are the same, building A is around 100.69 feet taller than building B.

Answer 2

Answer:

It is Building A is 50.34 feet taller than Building B. You are supposed to subtract both values.

Step-by-step explanation: