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Phoenix [80]
2 years ago
7

For a set population, does a parameter ever change? sometimes always unknown never if there are three different samples of the s

ame size from a set population, is it possible to get three different values for the same statistic? data from samples may vary from sample to sample, and so corresponding sample statistics may vary from sample to sample. data from samples never vary from sample to sample, and so corresponding sample statistics never vary from sample to sample. data from samples never vary from sample to sample, and so corresponding sample statistics may vary from sample to sample. data from samples may vary from sample to sample, and so corresponding sample statistics never vary from sample to sample.
Mathematics
1 answer:
Levart [38]2 years ago
5 0

For a set population, does a parameter ever change?

Answer: For a set population, a parameter never change.

Because while computing the parameter each and every unit of the population is studied. Therefore, we can not expect a parameter to vary.

If there are three different samples of the same size from a set population, is it possible to get three different values for the same statistic?

Answer: Data from samples may vary from sample to sample, and so corresponding sample statistic may vary from sample to sample.

Because while calculating the sample statistic, we consider only the part of population. Every time we draw a sample from population, there is every possibility of getting different sample. Therefore, data from samples may vary from sample to sample and corresponding sample statistic may vary from sample to sample.

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If the measures of two complimentary angles are 7x and 11x , then find x
Irina18 [472]
As you know that sum of complementary angles equal 90°

so,

7x + 11x = 90
18x = 90
x = 90/18
x =5


so,
option A is the correct one.
3 0
2 years ago
Read 2 more answers
Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. From the shipment you take
MrRissso [65]

Answer:

mean (μ) = 4.25

Step-by-step explanation:

Let p = probability of a defective computer components = \frac{68}{400} = 0.17

let q = probability of a non-defective computer components = \frac{332}{400} = 0.83

Given random sample n = 25

we will find mean value in binomial distribution

The mean of binomial distribution = np

here 'n' is sample size and 'p' is defective components

mean (μ) = 25 X 0.17 = 4.25

<u>Conclusion</u>:-

mean (μ) =  4.25

6 0
2 years ago
For 2, use the relationship between the values of the digits to solve Write a number in which the value of the 3 is ten times gr
larisa [96]

Answer:

New Digit = 315,864

Step-by-step explanation:

Given:

Digit - 135,864

Value of digit 3 = 30,000

Find:

New Digit, Value of 3 is 10 times greater

Computation:

Value of 3 is 10 times greater = (30,000) = 300,000

New Digit = 315,864

8 0
2 years ago
The profit earned by a sporting goods outlet is modeled in the graph below, where x is the number of years since the outlet open
LenaWriter [7]

The domain would be x ≥ 0.

This is because the outlet cannot have profit before it was open. Therefore, the growth must be from year 0 to present. If they give a year as starting, you can have an upper limit too, but there is not enough information here to determine that information.

4 0
2 years ago
Read 2 more answers
Meeting at least one person with the flu in thirteen random encounters on campus when the infection rate is 2% (2 in 100 people
s344n2d4d5 [400]

Answer:

23.1% probability of meeting at least one person with the flu

Step-by-step explanation:

For each encounter, there are only two possible outcomes. Either the person has the flu, or the person does not. The probability of a person having the flu is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Infection rate of 2%

This means that p = 0.02

Thirteen random encounters

This means that n = 13

Probability of meeting at least one person with the flu

Either you meet none, or you meet at least one. The sum of the probabilities of these outcomes is 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{13,0}.(0.02)^{0}.(0.98)^{13} = 0.7690

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.769 = 0.231

23.1% probability of meeting at least one person with the flu

6 0
2 years ago
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