For an investment with an interest rate compounded continuously, the formula would be
F = Pe^(rn), where r is the annual interest rate and n is the number of years.
F = 1050e^(0.055*5)
F = $1382.36
I hope I was able to answer your question.
A. The number of 10-boards Peter bought is equal to n divided by 10. Then, each of the 10-boxes will get two boxes of nails. The number of boxes of nails that Peter will have after buying n boards will be,
N = (2)(n/10)
Simplifying,
<em> N = n/5</em>
b. If the number of boards are 90 then,
N2 = (90/10)(2)(100 nails/box)
N2 = 1800
Answer: 1800
First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Answer:
0.7673
Step-by-step explanation:
We have the following:
The null and alternative hypothesis is,
H0: m = 290
Ha: m> 290
x = 285.2
m = 290
sd = 59.3
n = 82
is m the mean, sd the standard deviation and n the population size
Now we calculate the value of z like this:
z = (x - m) / sd / (n ^ (1/2))
z = (285.2 - 290) / 59.3 / (82 ^ (1/2))
z = -0.73
now
P (z> -0.73) = 1 - P (z <-0.73)
we look at the normal distribution table
P = 1 - 0.2327 = 0.7673
Therefore the value of p is equal to 0.7673