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2 years ago

An elevator in a tall building goes up 7 floors, then

Mathematics

1 answer:

3241004551 [841]2 years ago

5 0

Answer: he started on 14th floor

Step-by-step explanation:

14 + 7 - 9 - 4 + 8 - 2= 14

It started on floor 14

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Prove that x is a subset of y then x union z is a subset of y union z for all sets x y and z

Ganezh [65]

We are to show that if X ⊆ Y then (X ∪ Z) ⊆ (Y ∪ Z) for sets X, Y, Z.

Assume that a is a representative element of X, that is, a ∈ X. By the definition of union, a ∈ X ∪ Z. Now because X ⊆ Y and we assumed a ∈ X, then a ∈ Y by the definition of subset. And because a ∈ Y, then a ∈ Y ∪ Z by definition of union.

We chose our representative element, a, and showed that a ∈ X ∪ Y implies that a ∈ Y ∪ Z and this completes the proof.

4 0

1 year ago

Tickets to a play are $12.00 for adults. Children receive a discount and only have to pay $8.00. If 40 people attend the play an

MrRa [10]

30 were adults and 10 were children :) just add it up

3 0

1 year ago

HELP!! Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Rashid [163]

Answer:

85%

Step-by-step explanation:

You are given the function $S(n)=20\cdot b^n.$

If n is the number of hours, then initially n=0 and

$S(0)=20\cdot b^0=20\cdot 1=20.$

If S(n) is the function of exponential growth, then it can be represented as

$S(n)=I\cdot (1+r)^n,$

where I is the initial amount, r -is the percent growth rate and n is the number of hours.

If b = 1.85, we can represent it as b = 1 + 0.85. Thus, the hourly percent growth rate of the bacteria would be 0.85=85%.

8 0

1 year ago

Read 2 more answers

Player V and Player M have competed against each other many times. Historical data show that each player is equally likely to wi

Helen [10]

Answer:

0.46 (46%)

Step-by-step explanation:

We have the following data:

- Probability that player V wins the first set:

$p(1)=0.50$

(because the text says the two players are equally likely to win the first set)

- Probability that player V wins the 2nd set if he has won the 1st set:

$p(2|1)=0.60$

So, the probability that player V wins the first 2 sets is:

$p(12)=p(1)\cdot p(2|1)=(0.50)(0.60)=0.30$ (1)

Instead, the probability that player V loses the 2nd set if he has won the 1st set is 0.40 (=1-0.60), so

$p(2^c|1)=0.40$

So, the probabiity that player V winse the 1st set but loses the 2nd set is

$p(12^c)=p(1)\cdot p(2^c|1)=(0.50)(0.40)=0.20$ (2)

Also, we have:

- Probability that player V loses the 1st set:

$p(1^c)=0.50$

- Probability that she will lose the 2nd set in this case is 0.70, it means that the probability that she will win the 2nd set if she lost the 1st set is 0.30, so:

$p(2|1^c)=0.30$

So, the probability that she will lose the 1st set and win the 2nd set is:

$p(1^c2)=p(1^c)\cdot p(2|1^c)=(0.50)(0.30)=0.15$ (3)

Combined together (2) and (3), this means that the probability that player V wins exactly 1 set out of the first two sets is:

$p(1/2)=p(12^c)+p(1^c2)=0.20+0.15=0.35$ (4)

At this point, the probability that she will win the 3rd set is

$p(3)=0.45$

This means that the overall probability that she will win the 3rd set if she won exacty 1 of the first 2 sets is:

$p(1/2,3) = p(1/2)\cdot p(3)=(0.35)(0.45)=0.16$ (5)

So, the overall probability that player V will win a match against player M is the sum of (1) and (5):

$p(W)=p(12)+p(1/2,3)=0.30+0.16=0.46$

5 0

2 years ago

Decide whether the function is an exponential growth or exponential decay function, and find the constant percentage rate of gro

frosja888 [35]

Consider the function f ( x ) = 2479 ⋅ 0.9948x First compare this with f ( x ) po ( 1 + r ) ^ 2 We get po = 2479 And 1 + r = 0.9948 = 1 – 0.0052 r = -0.0052 < 0 Therefore, f is an exponential decay function with a decay rate of 0.0052 x 100 = 0.52%

8 0

2 years ago