I believe the answer is B) -3/2 or -1.5.
Please give a heart and rating if this is right!
Answer:
15 degrees
Step-by-step explanation:
Draw a horizontal segment approximately 4 inches long. Label the right endpoint A and the left endpoint C. Label the length of AC 4.2 meters. That is the horizontal distance between the eye and the blackboard.
At the right endpoint, A, draw a vertical segment going up, approximately 1 inch tall. Label the upper point E, for eye. Label segment EA 1 meter since the eye is 1 meter above ground.
At the left endpoint of the horizontal segment, point C, draw a vertical segment going up approximately 2 inches. Label the upper point B for blackboard. Connect points E and B. Draw one more segment. From point E, draw a horizontal segment to the left until it intersects the vertical segment BC. Label the point of intersection D.
The angle of elevation you want is angle BED.
The length of segment BC is 2.1 meters. The length of segment CD is 1 meter. That means that the length of segment BD is 1.1 meters.
To find the measure of angle BED, we can use the opposite leg and the adjacent leg and the inverse tangent function.
BD = 1.1 m
DE = 4.2 m
tan <BED = opp/adj
tan <BED = 1.1/4.2
m<BED = tan^-1 (1.1/4.2)
m<BED = 15
Answer: 15 degrees
Answer:
B or (-1)(1/2)(-1)(1)
Step-by-step explanation:
-4/5 is closest to (-1)
3/5 is closest to 1/2
-6/7 is closest to (-1)
5/6 is closest to 1
hope this helps
<span>You are asked to draw circle O with radius 12. Then draw radii OA and OB to form an angle with the measure named. You are asked to find the length of AB. The answers for each of the following measures are:
1)Measure of AOB=90, AB = 16.97 units
2)measure of AOB=180, AB = 24 units
3) measure of AOB=60, AB = 10.39 units
3) measure of AOB=120, AB = 10.39 units</span>
Step-by-step explanation:
Maths
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if 2
2008
−2
2007
−2
2006
+2
2005
=k ⋅2
2005
then the value of k is equal to
Answer
Correct option is
B
3
2
2008
−2
2007
−2
2006
+2
2005
=k⋅2
2005
⇒[2
2008
−2
2006
]−[2
2007
−2
2005
]=k⋅2
2005
⇒2
2006
(2
2
−1)−2
2005
(2
2
−1)=k⋅2
2005
⇒3(2
2006
−2
2005
)=k⋅2
2005
⇒3[2
2005
(2−1)]=k⋅2
2005
⇒3(2
2005
)=k⋅2
2005
On comparing, we get
k=3
Hence, Option B is correct.
