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2 years ago

6

The result of which expression will best estimate the actual product of (Negative four-fifths) (three-fifths) (Negative StartFra

ction 6 over 7 EndFraction) (five-sixths)?
(Negative 1) (one-fourth) (Negative 1) (negative 1)
(Negative 1) (one-half) (Negative 1) (1)
(Negative StartFraction 4 over 2 EndFraction) (Three-halves) (Negative two-fifths) (Five-halves)
(Negative three-fourths) (Negative three-fourths) (Negative one-fifth) (One-half)

1 answer:

Natasha_Volkova [10]2 years ago

7 0

Answer:

B or (-1)(1/2)(-1)(1)

Step-by-step explanation:

-4/5 is closest to (-1)

3/5 is closest to 1/2

-6/7 is closest to (-1)

5/6 is closest to 1

hope this helps

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T= 300 (d−15) 2 +20space, T, equals, start fraction, left parenthesis, d, minus, 15, right parenthesis, start superscript, 2,

stealth61 [152]

As can be read from your statement written "T, equals, start fraction, left parenthesis, d, minus, 15, right parenthesis, strt superscript, 2, end superscript, divided by, 300, end fraction, plus, 20", I hope your model equation is this :

$T = \frac{(d-15)^{2}}{300} + 20$

Hope this is your question, if not I think you will, still be able to find an answer of your question based on this solution

As we have to find lowest average temperature, So for minimum of a function its derivative is equal to 0 there.

So lets find derivative of T function first

So first expand $(d-15)^{2}$ as (d-15)(d-15)

we will use FOIL to multiply these

so $(d-15)(d-15) = d^{2} -15d -15d +225$

$= d^{2} -30d +225$

so we have $T = \frac{d^{2} -30d +225}{300} +20$

Now we will derivate each term here,300 in denominator is constant so that will come as it in in denominator.

To derivate terms in $dx^{2} -30d +225$ we will use power rule formula:

$(x^{n} )'= nx^{n-1}$

so derivative of $(d^{2} )'= 2d^{2-1} = 2d^{1} = 2d$

Then derivative of d will be 1

so that of -30d will be -30

then derivate of constant -225 will be 0

so we will have derivative as $\frac{2d-30}{300}$ for the fraction part and then derivative of +20 is again 0 as its constant term

$T' = \frac{2d-30}{300}$

For minimum we will put this derivative =0

$0 = \frac{2d-30}{300}$

Now solve for d

times both sides by 300

$0 \times 300 = \frac{2d-30}{300} \times 300$

$0 = 2d-30$

$0 +30 = 2d -30 +30$

$30 = 2d$

$\frac{30}{2} = \frac{2d}{2}$

$15 = d$

So now we have to find value of lowest temperature.

For that simply plug 15 in d place in original T function equation

$T = \frac{(d-15)^{2}}{300} + 20$

$T = \frac{(15-15)^{2}}{300} + 20$

$T = 20$

So T = 20 °C is the lowest average temperature and the answer.

6 0

2 years ago

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Suppose that demand in period 1 was 7 units and the demand in period 2 was 9 units. Assume that the forecast for period 1 was fo

Zepler [3.9K]

Answer:

Step-by-step explanation:

Forecast for period 1 is 5

Demand For Period 1 is 7

Demand for Period 2 is 9

Forecast can be given by

$F_{t+1}=F_t+\alpha (D_t-F_t)$

where

$F_{t+1}=Future Forecast$

$F_t=Present\ Period\ Forecast$

$D_t=Present\ Period\ Demand$

$\alpha =smoothing\ constant$

$F_{t+1}=5+0.2(7-5)$

$F_{t+1}=5.4$

Forecast for Period 3

$F_{t+2}=F_{t+1}+\alpha (D_{t+1}-F_{t+1})$

$F_{t+2}=5.4+0.2\cdot (9-5.4)$

$F_{t+2}=6.12$

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2 years ago

Mrs. Taft keeps inventory of the copy paper in the school copier room. Nine weeks ago, there were 150 reams of copy paper in the

Novay_Z [31]

Answer:

-9/65

Step-by-step explanation:

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2 years ago

A marina is in the shape of a coordinate grid. Boat A is docked at (2.4, −3) and Boat B is docked at (−3.4, −3). The boats are _

Tasya [4]

They are 5.8 units apart

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2 years ago

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Sections of prefabricated fencing are each 4 1/3 feet long. how long are 6 1/2 sections placed end to end

zalisa [80]

we know that

$4\frac{1}{3}= \frac{(4*3+1)}{3} =\frac{13}{3}$

$6\frac{1}{2}= \frac{(6*2+1)}{2}=\frac{13}{2}$

To find how long are $6\frac{1}{2}$ sections placed end to end

Multiply the number of sections by the length of one section

so

$\frac{13}{2} *\frac{13}{3} =\frac{169}{6}\ ft$

$\frac{169}{6}\ ft =28\frac{1}{6}\ ft$

therefore

<u>the answer is</u>

$28\frac{1}{6} \ ft$

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2 years ago

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