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1 year ago

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Thomas wants to estimate the mean height of students attending his college. He records the heights of 25 randomly selected stude

nts attending the college. What is the parameter?A. the heights of the randomly selected studentsB. the mean height of all students attending the collegeC. the mean height of the randomly selected studentsD. the 25 randomly selected studentsE. all the students attending the college

1 answer:

Nadya [2.5K]1 year ago

7 0

Answer: B - The mean height of all the students of the college.

Explanation:

In statistics, the concept of parameter refers to the value that you want to know about a population to characterize it, for example, mean height, mean age, etc.

In this case, the value that you want to know about the population of the college is the mean height of its students, so the correct option is B.

The following concepts are used in statistics that can be applied to the given example:

- Population (all students of the university).

- Parameter (mean height of university students).

- Sample (the 25 randomly selected students).

- Elements (the heights of the selected students).

- Estimator (average height of randomly selected students).

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1 year ago

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal. During one

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Answer:

0.82 = 82% probability that at least one party will not order drinks

Step-by-step explanation:

For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.

This means that $p = 0.75$

During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

6 parties, so n = 6.

Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So

$P(X = 6) + P(X < 6) = 1$

We want P(X < 6). So

$P(X < 6) = 1 - P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.18$

$P(X < 6) = 1 - P(X = 6) = 1 - 0.18 = 0.82$

0.82 = 82% probability that at least one party will not order drinks

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Given a soda can with a volume of 36 and a diameter of 4, what is the volume of a cone that fits perfectly inside the soda can?

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First we need to find the heigh of the soda can be rearanging the volume formula, $V = pi * r^2* h$ . We can make that $h = \frac{V}{pi * r^2}$ We know that V is 36 and radius is half of the diameter, so radius is 2. $h = \frac{36}{pi * 2^2}$
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zaharov [31]

Answer:

Hence, the number of daylilies in the first year were:

600

Step-by-step explanation:

It is given that:

the recursive formula $a_n=1.5(a_{n-1})-100$ represents the number of daylilies, a, after n years.

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$a_5=2225$

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This means that:

$a_5=1.5(1.5a_3-100)-100\\\\a_5=(1.5)^2a_3-100\times (1.5)-100$

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$a_3=1.5a_2-100$

so,

$a_5=(1.5)^2\times (1.5a_2-100)-100\times (1.5)-100\\\\a_5=(1.5)^3a_2-(1.5)^2\times 100-(1.5)\times 100-100$

and so, putting $a_2$ in terms of $a_1$ we get:

$a_5=(1.5)^4a_1-(1.5)^3\times 100-(1.5)^2\times 100-(1.5)\times 100-100$

Now on putting the value of $a_5$ we find the value of $a_1$

$2225-(1.5)^4a_1-337.5-225-150-100\\\\2225=5.0625a_1-812.5\\\\2225+812.5=5.0625a_1\\\\3037.5=5.0625a_1\\\\a_1=\dfrac{3037.5}{5.0625}\\\\a_1=600$

Hence, the number of daylilies in the first year were:

600

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