answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mekhanik [1.2K]
2 years ago
15

NO JOKE 70 POINTS!!!!!!!! I WILL GIVE BRANLIEST AND RATE!!!! MATH EXPERTS COME HELP!!! AT LEAST TAKE A LOOK!!! LIKE WHERE ARE TH

E GENIUSES!!EASY I AM JUST DUMBREAD THIS AND THEN ANSWER THE QUESTION
READ THIS THEN ANSWER THE QUESTION:
There are so many items for sale in our world! Some of the items you can buy will appreciate in value. This means that as time passes, the value of the item increases. If you decide to sell the item at a later time, you should be able to sell it for more than you paid. Some common examples of items that appreciate in value include houses, stocks, and some types of art.
Other items you can buy will depreciate in value. This means that as time passes, the value of the item decreases. If you decide to sell the item at a later time, you will likely have to sell it for less than you paid for it. Cars, game systems, and jewelry are examples of items that usually depreciate as time passes. The majority of items that depreciate never reach a value of $0. Their worth attains some minimum, positive value that is greater than $0 and then their price stabilizes.
In 1981, IBM manufactured and sold one of the first personal computers. The machine was called the IBM Personal Computer (PC) 5150 and the full model retailed for $3,000. Similar to modern technology, the value of this item depreciated over time. The function that models how the PC 5150 depreciated as time passed is , where x is the number of years after 1981 and f(x) is the value of the PC 5150.


1. Evaluate the depreciation function at f(0). Show your work and use function notation as needed. What does this number represent?

2. Find the vertex of the depreciation function. What does this point represent in context of this problem? Show your work and explain your process.
Mathematics
2 answers:
german2 years ago
8 0

[just answering so you can give the other guy brainiest]

Rufina [12.5K]2 years ago
7 0

Answer:

The quadratic equation is f(x)=20x^{2} -400x +3000.

1. This number represents the amount of money it was sold for.

2. Vertex =(10,1000)

Step-by-step explanation:

This point represents the amount of money the computer was worth at its lowest point.

You might be interested in
Jacob’s daily tips this work week were $99, $78, $58, $91, $90, and $68. Is Jacob correct in thinking that the mean best represe
alexandr1967 [171]
Jacob is correct in thinking that because the mean represents the average of several quantities
3 0
2 years ago
Read 2 more answers
On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above
Charra [1.4K]

Answer:

y\geq\frac{1}{3}x-1

Step-by-step explanation:

A solid straight line has a positive slope and goes through (0, negative 1) and (3, 0)

<em>Find the slope of the solid line</em>

m=(0+1)/(3-0)\\\\m=\frac{1}{3}

The equation of the solid line in slope intercept form is equal to

y=mx+b

we have

m=\frac{1}{3}

b=-1 ---> given problem

substitute

y=\frac{1}{3}x-1

Everything above and to the left of the line is shaded

so the inequality is equal to

y\geq\frac{1}{3}x-1

8 0
2 years ago
Read 2 more answers
Deana's Deli has a mean delivery time of 23 minutes with a standard deviation of 2 minutes. Determine the z-score for the number
LekaFEV [45]

Answer:

o.5

Step-by-step explanation:

8 0
2 years ago
Solve the inequality. 2(4x – 3) ≥ –3(3x) + 5x? x ≥ 0.5 x ≥ 2 (–∞, 0.5]
marin [14]
2(4x - 3) > = -3(3x) + 5x
8x - 6 > = -9x + 5x
8x - 6 > = - 4x
-6 > = -4x - 8x
-6 > = - 12x
-6/-12 < = x
0.5 < = x or x > = 0.5 <==

** if u multiply/divide by a negative, the inequality sign changes
4 0
2 years ago
Read 2 more answers
Pete took a sample of moviegoers to see how many are seeing a comedy. Sample size: 175 Number seeing a comedy: 42 Population: 1,
Anastaziya [24]

Answer: Part A : c = n.p

Part B = 366 moviegoers

Step-by-step explanation: In part A, to predict the number of moviegoers, we have to find the <u>proportion</u> of the sample that does the activity, which will called <u>p</u>. Since <u>p</u> is a percentage, to determine how many moviegoers are seeing a comedy, you multiply it by the sample size, <u>n</u>.

Therefore: c = n.p

For part B, based on the the sample:

p = \frac{42}{175} = 0.24

The total population is given: 1,525

c = 0.24.1,525

c = 366

Based on the sample, <u>366</u> <u>people</u> are seeing a comedy.

3 0
2 years ago
Other questions:
  • Jarred sells DVDs. His inventory shows that he has a total of 3,500 DVDs. He has 2,342 more contemporary titles than classic tit
    11·2 answers
  • Which phrase best describes the translation from the graph y = (x – 5)2 + 7 to the graph of y = (x + 1)2 – 2? A. 6 units left an
    8·2 answers
  • Chris’ taxable income is $60,709. She is married, filing jointly. What is her tax?
    7·2 answers
  • A waitress works 1.75 hours less in the afternoon than in the evening. If she works 5      1/8
    6·1 answer
  • Frank read 5/9 of a book one day. The next day he read 3/5 of what he read on the first day. What fraction of the book did Frank
    10·1 answer
  • The formula for the volume of a sphere is V=4/3pir^3. What is the formula solved for r
    8·2 answers
  • One nanometer equals about
    8·1 answer
  • The histogram to the right represents the weights​ (in pounds) of members of a certain​ high-school programming team. What is th
    15·1 answer
  • A store ships cans by weight. A small box can hold 3 to 5 pounds. A medium box can hold 5 to 8 pounds. A large box can hold 8 to
    6·1 answer
  • Which expression is equivalent to the following complex fraction? StartFraction 2 Over x EndFraction minus StartFraction 4 Over
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!