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padilas [110]
2 years ago
6

A ship is carrying 10,250 pounds of individually boxed TV sets. If each box weighs 20.5 pounds, how many boxes are on the ship?

Mathematics
2 answers:
joja [24]2 years ago
5 0

divide total weight by weight of each box

10250 / 20.5 = 500 boxes total

ololo11 [35]2 years ago
3 0
There are 500 boxes on the ship
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Two students are reading a novel. Ashley reads 10 pages per day. Carly reads 8 pages per day , but she started early and is alre
erastova [34]

Answer:

For Ashley, p=10d+0

For Carly, p=8d+40

Step-by-step explanation:

Ashley: The slope is 10 (pages) times how many days have passed.

Her y-intercept is 0 because that is how many pages she read before starting.

P is the y-value because solving the equation (putting a number in for how many days it's been) will give you the number of pages she read.

Carly: The slope is 8 (pages) times how many days have passed.

Her y-intercept is 40 because that is how many pages she read before starting reading 8 per day.

8 0
2 years ago
Which questions best describes: A tire manufacturer has a 60,000 mile warranty for tread life. The manufacturer considers the ov
Angelina_Jolie [31]

This question is incomplete as it didn't provide the answer choices. The complete question was gotten from google as:

Which questions best describes: A tire manufacturer has a 60,000 mile warranty for tread life. The manufacturer considers the overall tire quality to be acceptable if less than 5% are worn out at 60,000 miles. The manufacturer tests 250 tires that have been used for 60,000 miles. They find that 3.6% of them are worn out. With this data, we test the following hypotheses. H 0: The proportion of tires that are worn out after 60,000 miles is equal to 0.05. H a: The proportion of tires that are worn out after 60,000 miles is less than 0.05. In order to assess the evidence, which question best describes what we need to determine?

a. If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be 3.6% or less?

b. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be 5%?

c. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be less than 5%?

d. If we examine the proportion of worn out tires in the population of tires used for 60,000 miles, how likely is that proportion to be 3.6%?

e. If we examine a sample of tires used for 60,000 miles and determine the proportion that are worn out, how likely is that proportion to be less than 5%?

Answer:

Option A is the correct answer choice - If we examine a sample of tires used for 60,000 miles and determine the proportion that is worn out, how likely is that proportion to be 3.6% or less?

Step-by-step explanation:

The question that best describes what we need to determine is stated in option A as this will give us p-value and we will guide us in deciding whether to keep or reject the null hypothesis.

Therefore, option A is the correct answer - If we examine a sample of tires used for 60,000 miles and determine the proportion that is worn out, how likely is that proportion to be 3.6% or less?

6 0
2 years ago
A mountaineer climbed 1,000 feet at a rate of x feet per hour. He climbed an additional 5,000 feet at a different rate. This rat
yKpoI14uk [10]
Your question asks for an expression, so you would expect an answer in the form of an equation containing variables. This is because you have only 2 independent equations with 3 unknowns. That makes the system unsolvable. 

Suppose v₁ is the mountaineer's velocity during the 1,000-foot trail. Then, v₂ is his speed for the 5,000-foot trail. The equation relating these two variables is:

v₂ = 2v₁ - 10 ---> equation 1

Then, you find the equation for the total number of hours he climbed. That would be the distance divided by their respective speed.

t = 1000/v₁ + 5000/v₂ ----> equation 2

Substituting equation 1 to equation 2,

t = 1000/v₁ + 5000/(2v₁ - 10)
t = 1000/v₁ + 5000/2(v₁-5)
t = 1,000/v₁ + 2,500/(v₁-5) 
3 0
2 years ago
Jimmy has listed the amount of money in his wallet for each of the last ten days. He decides to remove day 7, as that was payday
abruzzese [7]

Answer:

The mean will reduce

Step-by-step explanation:

The total amount of money for the ten days divided by number of days will give mean 1, M₁

Removing the value for day seven will reduce the sum of money as it will be for 9 days only.In finding the mean, you will divide by 9 days to get mean M₂

Mean M₂ < M₁

8 0
2 years ago
During an experiment, Juan rolled a six-sided number cube 18 times. The number two occurred four times. Juan claimed the experim
Maru [420]

Answer:

1) Juans claim is incorrect. The correct experimental probablilty is 2/9

Step-by-step explanation:

8 0
2 years ago
Read 3 more answers
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