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Alona [7]
1 year ago
6

What is the greatest whole number that will divide both 792 and 990 exactly

Mathematics
2 answers:
Nastasia [14]1 year ago
8 0
Factor the numbers, starting from the smallest:
792=2*3*3*11*4
990=2*3*3*11*5
the greatest whole number that can be divided by both 792 and 990 is 2*3*3*11=198
the smallest whole number that can divide both 792 and 990 exactly is 2*3*3*11*4*5=3960

Not sure which one you are asked to find. 
Eduardwww [97]1 year ago
6 0
I believe the answer is 198
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Let p, q, and r be the propositions p: You get an A on the final exam. q: You do every exercise in this book. r: You get an A in
babunello [35]

Answer:

a) r ^ ¬q

b) p ^ꓥqꓥ^ r

c) r → p

d) p ^ ¬qꓥ^ r

e) (p ^ q) → r

f) r ↔ (q v p)

Step-by-step explanation:

 

 

ꓥ^ = AND Conjunction

vꓦ = OR disjunction

¬ = NOT Negation

↔ = Double Implication

→ = implication

6 0
1 year ago
Lines K and L are parallel,and the measure of angle ABC is 19 degrees
Scorpion4ik [409]

Answer:

A. Because the measure of the angle BCD is 19 \° and the angles BCD  and ECF are Vertical angles. Therefore, they are congruent ( m\angle BCD=m\angle ECF =19\°)

B.  m\angle BCD=19\°

Step-by-step explanation:

<h3> <em><u>The missing figure is attached.</u></em></h3><h3 />

You can observe in the figure that the parallel lines k and l are intersected by a another line m (this is a transversal).

Let's begin with PART B:

Observe that the angles ABC and BCD are located inside the parallel lines and they alternate sides of the transversal. Therefore, we can determine that these angles are "Alternate Interior Angles".

Since the lines k and l are parallel, we know that the Alternate Interior Angles are congruent. Then:

m\angle ABC=m\angle BCD=19\°

Now we can solve the PART A.

Observe the figure.

Since the angle BCD  and the angle ECF share the same vertex, they are "Vertical angles" and, therefore, they are congruent:

m\angle BCD=m\angle ECF =19\°

8 0
2 years ago
Bonita is testing prototype model rocket engines. To be considered a successful launch, the rocket must reach a height of at lea
lbvjy [14]

Answer:

(0, 33)   : Yes

(4.8,  30.5)  : Yes


Step-by-step explanation:

height of at least 24 ft :  y >= 24

horizontal distance of no more than 10 ft. : 0 <= x <= 10

The vertical height must be at least three times as high as the horizontal distance. No rocket should go higher than 33 ft.:

y >=  3x and y <= 33

So Constraints:

24 <= y <= 33

y >= 3x

0 <= x <= 10

Now check to see if those coordinate points meet all the constraints

(0, 33)   : Yes

(4.8, 30.5)  : Yes

(9, 26)  : No (because 26 is less than (3 * 9) = 27)

(4, 36) : No (because 36 > 33,  must be 24 <= y <= 33)

(2, 22): No (because 22 <24,  must be 24 <= y <= 33)

5 0
1 year ago
A toy rocket is launched from a platform 33 feet above the ground at a speed of 83 feet per second. The height of the rocket in
kiruha [24]

Answer:

282ft

Step-by-step explanation:

83×3=249

249+33=282

4 0
1 year ago
Joaquin and Trisha are playing a game in which the lower median wins the game. Their scores are shown below.
iragen [17]
Median is defined as the middle term when the scores are arranged in increasing/decreasing order.

Joaquin's scores: 58, 62, 72, 75, 85, 91        Median: 73.5
Trisha's scores: 55, 74, 76, 90, 91, 92          Median: 83

The answer is letter A. 
3 0
1 year ago
Read 2 more answers
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