In which subject did students decline the most from 2000 to 2003?

Find the ratio of $22 to $5.50

solniwko [45]

Answer:

4:1

Step-by-step explanation:

22/5.50

divide numerator by denominator and denominator by denominator

22/5.50=4

5.50/5.50=1

4/1 or 4:1

4 0

2 years ago

Jar A contains four liters of a solution that is 45% acid. Jar B contains five liters of a solution that is 48% acid. Jar C cont

castortr0y [4]

Answer:

k= 80%

Step-by-step explanation:

Jar A contains 4*0.45 L acid, and 4 L of a solution of acid.

Jar B contains 5*0.48 L acid., and 5 L of a solution of acid.

Jar C contains 1*k/100 = k/100 acid, and 1 L of a solution.

50% = 0.5

For jar A.

(2/3)*k/100 L acid is added to jar A.

Now jar A contains 4*0.45 L + (2/3)*k/100 L acid, and it has (4+2/3)L of a solution.

L solute/L solution = 0.5

[4*0.45 L + (2/3)*k/100 L]/(4+2/3)L = 0.5

[1.8 + (2k/300)]/[(12+2)/3] = 0.5

[1.8 + (2k/300)]/[14/3] = 0.5

[1.8 + (2k/300)]= 0.5*(14/3)

(2k/300) = 0.5*(14/3) - 1.8

2k = (0.5*(14/3) - 1.8)*300

k = (0.5*(14/3) - 1.8)*300/2 =80

k= 80%

We also can find k using jar B.

(1/3)k/100 L acid is added to jar B.

Now jar B contains 5*0.48 L+ (1/3)k/100 L acid, and it has (5+1/3) L of a solution.

L solute/L solution = 0.5

[5*0.48 L+ (1/3)k/100 L ]/(5+1/3)L= 0.5

[5*0.48 + (1/3)k/100 ]/(5+1/3)= 0.5

This equation also gives k=80%

Check.

We can check at least for jar A.

Jar A has 4L solution and 4*0.45=1.8 L acid.

2/3 L of the solution from jar C was added, and now we have 4 2/3 L of solution.

(2/3)* 80%= (2/3)*0.8 acid was added from jar C.

Now we have [1.8 +(2/3)*0.8] L acid in jar A.

L solute/L solution = [1.8 +(2/3)*0.8] L /(4 2/3) L = 0.5 or 50% as it is given that jar A has 50% at the end.

7 0

2 years ago

This star is made up of 4 equilateral triangles of equal area and a square.

pentagon [3]

Answer:

24 cm

Step-by-step explanation:

Given: Picture of the star is made up of 4 unshaded equilateral triangles of equal area and a shaded square.

Area of the shaded region (square) = $9\,\, cm^2$

To find: the perimeter of the star

Solution:

Area of the shaded region (square) = $9\,\, cm^2$

Area of square = $(side)^2$

$(side)^2=9\\side=3\,\,cm$

As each equilateral triangle has side lengths that are the same as the side length of the square,

length of side of the star = 3 cm

Perimeter is the sum of lengths of the sides.

Perimeter of star = sum of 8 sides of the star

= 8 × 3 = 24 cm

4 0

2 years ago

Which statement best explains the relationship between lines FG and HJ?

Taya2010 [7]

Answer:they are not perpendicular because their slopes are not negative reciprocals.

Step-by-step explanation:

FG’s slope is 3/4 while HJ’s slope is 2/3. i just had this question on my test lol

5 0

2 years ago

Read 2 more answers

For each of the following, decide if the given series is a geometric series. A. 5+25x+125x2+625x3+3125x4+⋯ : Is this a geometric

Westkost [7]

Answer:

A. Yes.

B. Yes.

C. No.

Step-by-step explanation:

A. Yes. The sum of the series, $5 + 25x + 125x^{2} + 625x^{3} + 3125x^{4} + ...........$ is the sum of a geometric series.

The first term of the series $a_n$ = 5.

The common ration or the ratio between successive terms (r) = $\frac{25x}{5} = 5x$ (Answer)

B. Yes. The sum of the series, $5x^{7} + 5x^{8} + 5x^{9} + 5x^{10} + ............$ is also the sum of a geometric series.

The first term of the series $a_n = 5x^{7}$ .

The common ration or the ratio between successive terms (r) = $\frac{5x^{8} }{5x^{7} } = x$ (Answer)

C. No. The sum of the series, $5 + 5x + 5x^{2} + 5x^{4} + 5x^{8} + ...........$ is not the sum of a geometric series.

The first term of the series $a_n = 5$ .

(Answer)

5 0

2 years ago