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IrinaK [193]
2 years ago
6

By rewriting the formula for the Multiplication​ Rule, you can write a formula for finding conditional probabilities. The condit

ional probability of event B​ occurring, given that event A has​ occurred, is P (B A) = P (A and B) P (A).
Use the information below to find the probability that a flight arrives on time given that it departed on time.
1. The probability that an airplane flight departs on time is 0.91.
2. The probability that a flight arrives on time is 0.86.
3. The probability that a flight departs and arrives on time is 0.81.
Mathematics
1 answer:
ss7ja [257]2 years ago
5 0

Answer:

89.01% probability that a flight arrives on time given that it departed on time.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Departing on time

Event B: Arriving on time.

The probability that a flight departs and arrives on time is 0.81.

This means that P(A \cap B) = 0.81

The probability that an airplane flight departs on time is 0.91.

This means that P(A) = 0.91

Find the probability that a flight arrives on time given that it departed on time.

P(B|A) = \frac{0.81}{0.91} = 0.8901

89.01% probability that a flight arrives on time given that it departed on time.

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tekilochka [14]

Answer:

1

p(b) =  \frac{1}{6}

2

p(k) =  \frac{1}{3}

3

P(a) =  \frac{1}{3}

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

p(b) =  \frac{N}{n}

p(b) =  \frac{6}{36}

p(b) =  \frac{1}{6}

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

p(k) =  \frac{2}{6}

p(k) =  \frac{1}{3}

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

P(a) =  \frac{W}{L}

=> P(a) =  \frac{10}{30}

=> P(a) =  \frac{1}{3}

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2 years ago
Tim ran a quarter mile five times yesterday the table above shows the time of each run in minutes and seconds. For example the t
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The total number of degrees, D, in an n-sided polygon is given by the formula D=180(n-2). When Janelle solves for n, she gets n=
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<span>D = 180 * (n -2)
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Source:
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Answer:

Correct answer is:

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Total money raised by bracelets with yellow beads = Number of bracelets sold \times Money raised by sale of one such bracelet = 5y

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