A bag contains 100 marbles which are red, green, and blue. Suppose a student randomly selects a marble without looking, records
2 answers:
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Answer:
24.2(to the nearest tenth)
Step-by-step explanation:
The question is ungrouped data type
standard deviation =√ [∑ (x-μ)² / n]
mean (μ)=∑x/n
=
=33.3
x-μ for data 5, 5, 6, 12, 13, 26, 37, 49, 51, 56, 56, 84 will be
-28.3, -28.3, -27.3, -21.3, -7.3, 3.7, 15.7,17.7, 22.7,22.7,50.7
(x-μ)² will be 800.89, 800.89,745.29,453.69,53.29,13.69,246.49,313.29,515.29,515.29,2570.49
∑ (x-μ)² will be = 7028.59
standard deviation = √(7028.59 / 12)
=24.2
Answer:
The ordered pairs represent points on the line are
(4, 3) ⇒ C
(2, ) ⇒ D
(-8, -6) ⇒ E
Step-by-step explanation:
To find the ordered pairs represent points on the line, substitute x by the x-coordinate of each point, if the value of y equals the y-coordinate of the point, then the point is on the line.
∵ The equation is y = x
∵ The ordered pair is (8, )
→ Substitute x by 8
∴ y = (8)
∴ y = 6
∵ The value of y does not equal the y-coordinate of the ordered pair
∴ The ordered pair (8, ) does not represent a point on the line
∵ The ordered pair is (,
)
→ Substitute x by
∴ y = (
)
∴ y =
∵ The value of y does not equal the y-coordinate of the ordered pair
∴ The ordered pair (,
) does not represent a point on the line
∵ The ordered pair is (4, 3 )
→ Substitute x by 4
∴ y = (4)
∴ y = 3
∵ The value of y equal the y-coordinate of the ordered pair
∴ The ordered pair (4, 3) represents a point on the line
∵ The ordered pair is (2, )
→ Substitute x by 2
∴ y = (2)
∴ y =
∵ The value of y equal the y-coordinate of the ordered pair
∴ The ordered pair (2, ) represents a point on the line
∵ The ordered pair is (-8, -6 )
→ Substitute x by -8
∴ y = (-8)
∴ y = -6
∵ The value of y equal the y-coordinate of the ordered pair
∴ The ordered pair (-8, -6) represents a point on the line
We have the following equation:
If we graph this equation we realize that in fact this is an ellipse with major axis matching the y-axis. So we can recognize these characteristics:
1. Center of the ellipse:
The midpoint C<span> of the line segment joining the foci is called the </span>center<span> of the ellipse. So in this exercise this point is as follows:
</span>
2. Length of major axis:
The line through the foci is called the major axis<span>, so in the figure if you go from -5, at the y-coordinate, and walk through this major axis to the coordinate 1, the distance you run is the length of the major axis, that is:</span>
3. Length of minor axis:
The line perpendicular to the foci through the center is called the minor axis. So in the figure if you go from -2, at the x-coordinate, and walk through this minor axis to the coordinate 2, the distance you run is the length of the minor axis, that is:
4. Foci:
Let's find c as follows:
Then the foci are:
If we graph this equation we realize that in fact this is an ellipse with major axis matching the y-axis. So we can recognize these characteristics:
1. Center of the ellipse:
The midpoint C<span> of the line segment joining the foci is called the </span>center<span> of the ellipse. So in this exercise this point is as follows:
</span>
2. Length of major axis:
The line through the foci is called the major axis<span>, so in the figure if you go from -5, at the y-coordinate, and walk through this major axis to the coordinate 1, the distance you run is the length of the major axis, that is:</span>
3. Length of minor axis:
The line perpendicular to the foci through the center is called the minor axis. So in the figure if you go from -2, at the x-coordinate, and walk through this minor axis to the coordinate 2, the distance you run is the length of the minor axis, that is:
4. Foci:
Let's find c as follows:
Then the foci are: