Answer:
153.8 grams of sugar is needed
Step-by-step explanation:
Check the picture below.
since the rectangular pool is a 14x30, the top and bottom part of that rectangle in the picture are just a 3x30 piece and the sides are 3x8, so how many ft² is that?
A = a^2.....where " a " is the length of one side
A = 79
79 = a^2...take sqrt of both sides, eliminating the ^2
sqrt 79 = a
8.89 = a
so the length of one side is approximately 8.89 ft <==
The number you are in search of is -52.
To find this, we first have to write the equation that goes along with the sentence. For this, we need to take it one term at a time.
Negative sixteen (-16) plus (+) the quotient of a number and -4 (x/-4) is (=) -3.
Now put the parenthesis together
-16 + x/-4 = -3
Now we can solve this for x.
-16 + x/-4 = 3 ---> add 16 to both sides
x/-4 = 13 ----> multiply both sides by -4
x = -52
Hey
So my brother posted this on Yahoo
Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth. A right-angled triangle is formed. Length of side to the water-surface is 5 cm, the hypot is 7 cm.
<span>What you do now is the following: </span>
<span>Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7) </span>
<span>So θ is approx 44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8° </span>
<span>The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram. </span>
<span>Shaded area ≃ 88.8/360*area of circle - ½*7*7*sin88.8° </span>
<span>= 88.8/360*π*7² - 24.5*sin 88.8° </span>
<span>≃ 13.5 cm² </span>
<span>(using area of ∆ = ½.a.b.sin C for the triangle) </span>
<span>b) </span>
<span>volume of water = cross-sectional area * length </span>
<span>≃ 13.5 * 30 cm³ </span>
<span>≃ 404 cm³</span>
Hoped it Helped
