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lianna [129]
2 years ago
10

Keshawn is asked to compare and contrast the domain and range for the two functions.

Mathematics
2 answers:
vampirchik [111]2 years ago
6 0
He could include two statements:
-  The domain of both functions is all real numbers.
-  The range of g ( x ) is y > 0 
iVinArrow [24]2 years ago
3 0

Answer:

Hence, option 1 is correct.

Hence, last option is correct.

Step-by-step explanation:

We have given two function

f(x)=5x  and g(x)=5^x

Domain is the values x can take and

And range is the values y can take

Hence, x can take any real value in both the functions in f(x) and g(x)

Hence, option 1 is correct

Now, for range

range of f(x) can be any real number

But range of g(x) can be positive number

Hence, last option is correct.

Rest all options are incorrect.

You might be interested in
1. Three friends pooled their money to purchase a new game system that costs $298. One person
iragen [17]

Answer:

First person: $107

Second person: $98

Third person: $93

Step-by-step explanation:

Let be "f" the amount of money (in dollars) that the first person contributed to the purchase, "s" the amount of money (in dollars) that the second person contributed to the purchase and "t" the amount of money (in dollars) that the third person contributed to the purchase.

With the information given in the exercise, you can set up the following equations:

Equation 1 → f+s+t=298

Equation 2 → s=f-9

Equation 3 → t=f-14

Substitute the Equations 2 and 3 into the Equation 1 and then solve for "f":

f+(f-9)+(f-14)=298\\\\3f-23=298\\\\f=\frac{321}{3}\\\\f=107

Finally, substitute the value of "f" into the Equation 2 and then into the Equation 3, in order to find the values of "s" and "t".

Therefore, you get:

s=107-9\\\\s=98\\\\\\t=107-14\\\\t=93

5 0
2 years ago
Find, correct to the nearest degree, the three angles of the triangle with the vertices d(0,1,1), e( 2, 4,3) − , and f(1, 2, 1)
Ksju [112]
Well, here's one way to do it at least... 

<span>For reference, let 'a' be the side opposite A (segment BC), 'b' be the side opposite B (segment AC) and 'c' be the side opposite C (segment AB). </span>

<span>Let P=(4,0) be the projection of B onto the x-axis. </span>
<span>Let Q=(-3,0) be the projection of C onto the x-axis. </span>

<span>Look at the angle QAC. It has tangent = 5/4 (do you see why?), so angle A is atan(5/4). </span>

<span>Likewise, angle PAB has tangent = 6/3 = 2, so angle PAB is atan(2). </span>

<span>Angle A, then, is 180 - atan(5/4) - atan(2) = 65.225. One down, two to go. </span>

<span>||b|| = sqrt(41) (use Pythagorian Theorum on triangle AQC) </span>
<span>||c|| = sqrt(45) (use Pythagorian Theorum on triangle APB) </span>

<span>Using the Law of Cosines... </span>
<span>||a||^2 = ||b||^2 + ||c||^2 - 2(||b||)(||c||)cos(A) </span>
<span>||a||^2 = 41 + 45 - 2(sqrt(41))(sqrt(45))(.4191) </span>
<span>||a||^2 = 86 - 36 </span>
<span>||a||^2 = 50 </span>
<span>||a|| = sqrt(50) </span>

<span>Now apply the Law of Sines to find the other two angles. </span>

<span>||b|| / sin(B) = ||a|| / sin(A) </span>
<span>sqrt(41) / sin(B) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(41) / sqrt(50) = sin(B) </span>
<span>.8222 = sin(B) </span>
<span>asin(.8222) = B </span>
<span>55.305 = B </span>

<span>Two down, one to go... </span>

<span>||c|| / sin(C) = ||a|| / sin(A) </span>
<span>sqrt(45) / sin(C) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(45) / sqrt(50) = sin(C) </span>
<span>.8614 = sin(C) </span>
<span>asin(.8614) = C </span>
<span>59.470 = C </span>

<span>So your three angles are: </span>

<span>A = 65.225 </span>
<span>B = 55.305 </span>
<span>C = 59.470 </span>
8 0
1 year ago
Ali and Renu are buying concert tickets from a web site. ​ ​There is an 18% 18 % service fee for every ticket bought from the si
adelina 88 [10]

$ 25 was the cost of each ​ticket before applying the service fee.

<u>Step-by-step explanation:</u>

Given that the cost of two tickets including the service fee = $59

So, the cost of one ticket including the service fee =  \frac{59}{2} = \$ 29.5

Service fee on each ticket = 18%

Let the cost of 1 ticket without including the service fee = x

So, according to the data given in the question,

                     x+18 \% \text { of } x=29.5

                     x+\frac{18}{100} \times x=29.5

                    x+0.18 x=29.5

                    1.18 x=29.5

                    x=\frac{29.5}{1.18}=25

Hence, cost of each ticket before applying the service fee = $25

3 0
2 years ago
Please help quickly!!!!!!!!!!The area of the regular pentagon is 6.9 cm2. What is the perimeter? 2 cm 5 cm 10 cm 20 cm
pishuonlain [190]
10
random words to fill up 20 character minimum for answering questions :P
7 0
2 years ago
Read 2 more answers
Division of two quantities is expressed as the ____ of those two quantities.
andreev551 [17]


Division of two quantities is expressed as the  quotient of those two quantities.

The word quotient is derived from the Latin language. It is from the Latin word "quotiens" which means "how many times." A quotient  is the answer to a divisional problem. A divisional problem describes how many times a number will go into another. The first time that this word was known to have been used in mathematics was around 1400 - 1500 AD in England.

There are two different ways to find the quotient of two numbers.  One of them is through Fractions. The quotient of a fraction is the number obtained when the fraction is simplified. The other way to find a quotient is  by employing the long division method where the quotient  value is positioned above the divisor and dividend.
 


6 0
2 years ago
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