All categories

2 years ago

Keshawn is asked to compare and contrast the domain and range for the two functions.

2 answers:

6 0

He could include two statements:
- The domain of both functions is all real numbers.
- The range of g ( x ) is y > 0

iVinArrow [24]2 years ago

3 0

Answer:

Hence, option 1 is correct.

Hence, last option is correct.

Step-by-step explanation:

We have given two function

$f(x)=5x$ and $g(x)=5^x$

Domain is the values x can take and

And range is the values y can take

Hence, x can take any real value in both the functions in f(x) and g(x)

Hence, option 1 is correct

Now, for range

range of f(x) can be any real number

But range of g(x) can be positive number

Hence, last option is correct.

Rest all options are incorrect.

You might be interested in

(a) Suppose one house from the city will be selected at random. Use the histogram to estimate the probability that the selected

vodka [1.7K]

Answer:

a. 0.71

b. 0.9863

Step-by-step explanation:

a. From the histogram, the relative frequency of houses with a value less than 500,000 is 0.34 and 0.37

-#The probability can therefore be calculated as:

$P(500000)=P(x=0)+P(x=500)\\\\\\\\=0.34+0.37\\\\\\\\=0.71$

Hence, the probability of the house value being less than 500,000 is o.71

-From the info provided, we calculate the mean=403 and the standard deviation is 278 The probability that the mean value of a sample of n=40 is less than 500000 can be calculated as below:

$P(\bar X$

Hence, the probability that the mean value of 40 randomly selected houses is less than 500,000 is 0.9863

8 0

2 years ago

Your friend is trying to grow her hair as long as her cousin’s hair. The table shows their hair lengths y (in inches) in differe

Effectus [21]

<span>Given the table that shows the hair lengths y (in inches) of your friend and her cousin in different months x.

Month      Friends Hair(in)      Cousins Hair(in)
    3                     4                              7
    8                    6.5                            9.

To solve for the cousins hair, recall that the equation of a line is given by

y = mx + c

From the table,

7 = 3m + c . . . (1)
9 = 8m + c . . . (2)

(1) - (2) ⇒ -2 = -5m
$\Rightarrow m= \frac{2}{5} =0.4$

Substituting for m into equation (1) gives:

$7=3(0.4)+c \\ \\ \Rightarrow c=7-1.2=5.8$

Therefore, the equation representing the growth of the cousin's hair is given by y = 1.2x + 5.8
</span>

7 0

1 year ago

Find each product.<br> 1) (5n - 5)(4n - 4)

Paraphin [41]

Answer:

20n² - 40n + 20

Step-by-step explanation:

(5n - 5)(4n - 4)

= 5n(4n) + 5n(-4) - 5(4n) - 5(-4)

= 20n² - 20n - 20n + 20

= 20n² - 40n + 20

Another way to do this:

(5n - 5)(4n - 4)

= 5(n - 1) * 4(n - 1)

= 20(n - 1)(n - 1)

= 20(n - 1)²

= 20(n² - 2n + 1)

= 20n² - 40n + 20

6 0

2 years ago

Solve for x. −12 = − 3/4 x A) 6 B) 8 C) 12 D) 16

shepuryov [24]

Answer:

D) 16

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Anton will be constructing a segment bisector with a compass and straightedge, while Maxim will be constructing an angle bisecto

Genrish500 [490]

The similarities are;

Compass and a straight edge required for both construction

Both construction includes a line drawn from the intersection of arcs to bisect a segment or an angle

The bases for the construction of both bisector are the ends of segment and the angle to be bisected

The width of the compass when drawing intersecting arcs, is more than half the width of the segment or angle being bisected

The differences are;

Two points of intersection of arcs are used in the segment bisector while only one is requited in an angle bisector
The bisecting line crosses the segment in a segment bisector, while it stops at the vertex of the angle being bisected in an angle bisector

The sources of the above equations are as follows;

The steps to construct a segment bisector are;

Place the needle of the compass at one of the ends of the line segment to be bisected

Widen the compass so as to extend more than half of the length of the segment to be bisected

Draw two arcs, one above, and the other below the line

Place the compass needle at the other end and with the same compass width draw arcs that intersects with the arcs drawn in the above step

Draw a line segment by placing the ruler on the points of intersection of the arcs above and below the line

The steps to construct an angle bisector are;

With the compass needle at the vertex, open the pencil end such that arcs can be drawn on the rays (lines) forming the angle

Draw an arc on both lines forming the angle

Place the compass needle at one of the intersection points and draw an arc in between the lines forming the angle

Repeat the above step with the same compass width from the other intersection point with the rays forming the angle

Join the point of intersection of the two arcs to the vertex of the angle to bisect the angle

Therefore, we have;

The similarities are;

A compass and a straight edge can be used for both construction

A straight line is drawn from the point of intersection of arcs to bisect the segment or the angle

The arcs are drawn from the ends of the segment or angle to be bisected

The width of the compass is more than half the width of the line or angle when drawing the arcs

The differences are;

In a segment bisector, the intersection point is above and below the line, while in an angle bisector only one pair of arcs are drawn to intersect above the line

The bisecting line passes through the segment being bisected, while the line stops at the vertex in an angle bisector

Learn more about the construction of segment and angle bisectors here;

brainly.com/question/17335869

brainly.com/question/12028523

7 0

1 year ago