The square root of a number is a value that, when multiplied by itself, gives the number. Example: 4 × 4 = 16, so a square root of 16 is 4. But note that (−4) × (−4) = 16 also, so −4 is also a square root of 16. This is why each nonzero interger has two square roots.
The cube root of a number is a special value that, when used in a multiplication three times, gives that number. Example: 3 × 3 × 3 = 27, so the cube root of 27 is 3. But cube root is unlike square root where as -3 × -3 × -3 = -27 not 27 therefore there is only one cube root.
I hope this helps
Answer:
Therefore the expression is option A)
Step-by-step explanation:
Given:
Statement as ' 8 less than two times X'
To Find :
Expression for the statement
'8 less than two times X'
Solution:
Now 8 less than two times X means Subtract 8 from '2x'
Therefore the expression is option A)
Answer:
This question contains some errors; the correct question is:
You pack sandwiches for a mountain hike with your friends. Each sandwich takes 2 slices of bread, and each hiker eats one sandwich. How many slices of bread are used for n hikers? Write your answer as an expression.
The answer is:
(2n) slices of bread for n hikers
Step-by-step explanation:
According to the question, sandwiches packed for a mountain hike with friends is made of two (2) slices of bread.
Each hiker gets one sandwich
This, n hikers will get n× 1 sandwich
= (n) sandwiches.
If 1 sandwich contains 2 slices of bread, then (n) sandwiches for n hikers will contain:
(2 × n) slices of bread
That is, (2n) slices of bread.
The expression is (2n).
<span>The control box’s dimensions are 30 inches by 25 inches. Therefore, the perimeter of the box is 30 inches + 25 inches + 30 inches + 25 inches = 110 inches. There are 12 inches per foot. 12 goes into 110 nine times, with two inches left over. Therefore, 9 feet and 2 inches of weatherstripping is needed.</span>
Answer:
We have the functions:
f(x) = IxI + 1
g(x) = 1/x^3.
Now, we know that the composite functions do not permute.
How we can prove this?
First, two composite functions are commutative if:
f(g(x)) = g(f(x))
Well, you could use brute force (just replace the values and see if the composite functions are commutative or not)
But i will use a more elegant way.
We can notice two things:
g(x) has a discontinuity at x = 0.
so:
f(g(x)) = I 1/x^3 I + 1
still has a discontinuty at x = 0, but:
g(f(x)) = 1/( IxI + 1)^3
here the denominator is IxI + 1, is never equal to zero.
So now we do not have a discontinuity.
Then the composite functions can not be commutative.
