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Korolek [52]
2 years ago
6

Question 5 (3 points) The soccer team is planning to sell health bars for a fundraiser. The prices of purchasing health bars fro

m two different companies are represented by the system of equations shown, where x is the number of bars purchased and y is the total cost in dollars. Company A: y = 0.75x Company B: y = 10 + 0.50x How many bars would the team need to purchase from each company in order for the total cost to be equal?
Mathematics
2 answers:
Leni [432]2 years ago
8 0

the answer is 40 bars hope it helps

Ierofanga [76]2 years ago
3 0
The correct answer is 40 bars. 

In order to find this amount we have to find when the y values are worth the same. Since both equations are equal to y, we can set them equal to each other to find a time when the y values are the same. 

Company A = Company B
.75x = 10 + .50x ---> Now subtract .50x from both sides. 
.25x = 10 ---> Now divide both sides by .25
x = 40

When x = 40 it will cost $30 from both companies. 

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1 year ago
A belt and a pair of pants cost $490 altogether. A bag costs twice as much
m_a_m_a [10]

Answer:

$196

Step-by-step explanation:

Lets assume,

cost of a belt = 'x'

cost of a pair of pants = 'y'

Now, According to the question;

  1. x + y = 490;
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  3. cost of a pair of pants = twice the cost of bag

    ⇒ y = 2×2x ⇔ 4x

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2 years ago
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Step-by-step explanation:

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Because it does not specify that she has to choose one or two from each category all pieces of jewelry can be treated as choices in a combination set.

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C(n,r)= \frac{n!}{r!(n-r)!}

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C(11,4)= \frac{11!}{4!(11-4)!} 

She has 330 possible choices  to come home with 4 pieces of jewelry



5 0
2 years ago
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