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2 years ago

8

Matthew and his 3 siblings are wedding a flower bed with an area of 9 square yards. If they shared the job equally,how much squa

re yards of the flower bed will each child need to weed

1 answer:

Tatiana [17]2 years ago

4 0

The answer is 27 yards

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6 clients are throwing a party. Each cake serves 24 servings and has a party of 70 +3staff how many cakes are needed?

Airida [17]

4 cakes are needed fjfnccnfn

8 0

2 years ago

Read 2 more answers

Evelyn has $524.96 in her checking account. She must maintain a $500 balance to avoid a fee. She wrote a check for $32.50 today.

barxatty [35]

Answer:

524.96 − 32.50 + x ≥ 500

Amount need to deposit = $7.54

Step-by-step explanation:

Given:

Amount in checking account = $524.96

Maintain amount = $500

Amount of check = $32.50

Find:

Amount need to deposit

Computation:

Assume, amount need to deposit = x

So,

For avoiding fee

524.96 − 32.50 + x ≥ 500

x = 7.54

Amount need to deposit = $7.54

4 0

2 years ago

A project’s critical path is composed of activities A (variance .33), B (variance .67), C (variance .33), and D (variance .17).

julia-pushkina [17]

Answer:

The standard deviation on the critical path = 0.834

Step-by-step explanation:

Variance of activity A ( $V_{1}$ ) = 0.33

Variance of activity B ( $V_{2}$ ) = 0.67

Variance of activity C ( $V_{3}$ ) = 0.33

Variance of activity D ( $V_{4}$ ) = 0.17

Thus the standard deviation on the critical path ( $\alpha ^{2}$ ) = $V_{1} ^{2}$ + $V^2_{2}$ + $V^2_{3}$ + $V^2_{4}$

$\alpha ^{2}$ = $0.33^{2}$ + $0.67^{2}$ + $0.33^{2}$ + $0.17^{2}$

$\alpha ^{2}$ = 0.6956

$\alpha$ = 0.834

The standard deviation on the critical path = 0.834

4 0

2 years ago

Felipe planted some seeds for a science project. One of his plants grew 6 2/7 inches in the first week, and then it grew 5 11/14

MatroZZZ [7]

Answer:

<em>The plant grew </em> $12\frac{1}{14}$ <em> inches</em>

Step-by-step explanation:

<u>Operations with Fractions</u>

Felipe planted seeds for a science project. One of the plants grew 6 2/7 inches in the first week and 5 11/14 inches in the second week.

We are required to find the total growth during the two weeks. We have to find the sum of:

$6\frac{2}{7}+5\frac{11}{14}$

Let's convert both fractions to improper form:

$6\frac{2}{7}+5\frac{11}{14}=6+\frac{2}{7}+5+\frac{11}{14}$

Adding the integers:

$6\frac{2}{7}+5\frac{11}{14}=11+\frac{2}{7}+\frac{11}{14}$

Now we find the LCM of 7 and 14 is 14, thus:

$6\frac{2}{7}+5\frac{11}{14}=11+\frac{4}{14}+\frac{11}{14}$

$6\frac{2}{7}+5\frac{11}{14}=11+\frac{15}{14}=11+\frac{14+1}{14}$

$6\frac{2}{7}+5\frac{11}{14}=11+1+\frac{1}{14}$

$6\frac{2}{7}+5\frac{11}{14}=12+\frac{1}{14}$

Rewriting as a mixed number:

The plant grew $12\frac{1}{14}$ inches

8 0

2 years ago

Carla can choose two of her three pairs of sneakers to take to a track meet. If the pairs of sneakers are called A, B, and C, wh

Semenov [28]

Number of ways of choosing two pair of sneakers from three pairs named A, B, C is given by 3C2 (3 combination 2) = 3! / 2!(3 - 2)! = 3! / (2! x 1!) = (3 x 2) / (2 x 1) = 3.

Therefore, the sample space is given by S = {AB, AC, BC}

5 0

2 years ago

Read 2 more answers