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PilotLPTM [1.2K]
2 years ago
7

On a coordinate plane, a circle has a center at (negative 2, 0). Point (negative 2, 4) lies on the circle. Distance formula: Sta

rtRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot Does the point (1, StartRoot 7 EndRoot) lie on the circle shown? Explain. Yes, the distance from (–2, 4) to (–2, 0) is 4 units. Yes, the distance from (–2, 0) to (1, StartRoot 7 EndRoot) is 4 units. No, the distance from (–2, 0) to (1, StartRoot 7 EndRoot) is not 4 units. No, the distance from (–2, 4) to (1, StartRoot 7 EndRoot) is not 4 units.
Mathematics
2 answers:
Zigmanuir [339]2 years ago
8 0

Answer:

it is B

Step-by-step explanation:

vivado [14]2 years ago
4 0

Answer:

its B on Ed

Step-by-step explanation:

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The sum of Claudia's age and Pedro's age is
Drupady [299]

Answer:20

Step-by-step explanation:14+6=20

20-6=14

6 0
2 years ago
Consider the following formula used to estimate height, h, of a seedling after w weeks since planting:
svp [43]

Answer:

Option B. w=5h-8

Step-by-step explanation:

we have

h=(\frac{1}{5})w+(\frac{8}{5})

Solve for w

That means ----> isolate the variable w

Multiply by 5 both sides to remove the fraction

5h=w+8

subtract 8 both sides

5h-8=w+8-8

5h-8=w

Rewrite

w=5h-8

4 0
2 years ago
In triangle ABC segment DE is parallel to the side AC. (The endpoints of segment DE lie on the sides AB and BC respectively).
ivanzaharov [21]

Answer:

6 dm

Step-by-step explanation:

Triangle DBE is similar to triangle ABC, so their side lengths are proportional.

DE/AC = DB/AB

The length of DB can be found from ...

DB +AD = AB

DB = AB -AD = (15 -10) dm = 5 dm

So, we can fill in the proportion:

DE/(18 dm) = (5 dm)/(15 dm)

DE = (18 dm)·(1/3) . . . . . . . . . . simplify, multiply by 18 dm

DE = 6 dm

_____

It can be helpful to draw and label a figure.

5 0
2 years ago
Find where the slope of the curve is defined:<br> x^2y-xy^2=4
Natali [406]
You do the implcit differentation, then solve for y' and check where this is defined. 
In your case: Differentiate implicitly: 2xy + x²y' - y² - x*2yy' = 0 
Solve for y': y'(x²-2xy) +2xy - y² = 0 
y' = (2xy-y²) / (x²-2xy) 
Check where defined: y' is not defined if the denominator becomes zero, i.e. 
x² - 2xy = 0 x(x - 2y) = 0 
This has formal solutions x=0 and y=x/2. Now we check whether these values are possible for the initially given definition of y: 
0^2*y - 0*y^2 =? 4 0 =? 4 
This is impossible, hence the function is not defined for 0, and we can disregard this. 
x^2*(x/2) - x(x/2)^2 =? 4 x^3/2 - x^3/4 = 4 x^3/4 = 4 x^3=16 x^3 = 16 x = cubicroot(16) 
This is a possible value for y, so we have a point where y is defined, but not y'. 
The solution to all of it is hence D - { cubicroot(16) }, where D is the domain of y (which nobody has asked for in this example :-). 
(Actually, the check whether 0 is in D is superfluous: If you write as solution D - { 0, cubicroot(16) }, this is also correct - only it so happens that 0 is not in D, so the set difference cannot take it out of there ...). 
If someone asks for that D, you have to solve the definition for y and find that domain - I don't know of any [general] way to find the domain without solving for the explicit function). 
3 0
2 years ago
What is 3 times the sixth power of 10
sergey [27]
3000000...........
10^6 =1000000 (3) = 3000000
7 0
2 years ago
Read 2 more answers
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