H (t) = - 16t ^ 2 + 16t + 480
For this case, the first thing to do is to match the polynomial to zero to find the roots.
We have then:
0 = -16t ^ 2 + 16t + 480
From here, we obtain the following roots of the polynomial:
t1 = -5
t2 = 6
We ignore the negative root because the time is always greater than zero.
Answer:
it takes Rose to hit the water about
t = 6 seconds
Answer:
The 185th digit following that pattern of '12345678910111213141516' would be the number '5'
Step-by-step explanation:
The reason the 185th digit is '5' is because the pattern increases it's standard number by the following number (ex, 1,2,3,4,5, etc), and eventually it reached 185 as one of it's numbers, '5' would be the digit because the '18' part of 185 would only be the 184th digit, hence you are needed to include the '5' to complete the sequence of that number to reach the 185th digit.
Answer:
<h2>14mph</h2>
Step-by-step explanation:
Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;
m = −0.05x²+3.5x−49
when m= 9
9 = −0.05x²+3.5x−49
−0.05x²+3.5x−49 = 9
0.05x²-3.5x+49 = -9
Multiplying through by 100
5x²+350x−4900 = 900
Dividing through by 5;
x²+70x−980 = 180
x²+70x−980 - 180 = 0
x²+70x−1160 = 0
Using the general formula to get x;
a = 1, b = 70, c = -1160
x = -70±√70²-4(1)(-1160)/2
x = -70±√4900+4640)/2
x = -70±(√4900+4640)/2
x = -70±√9540/2
x = -70±97.7/2
x = -70+97.7/2
x = 27.7/2
x = 13.85mph
x ≈ 14 mph
Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph
Answer:
E(X) = 1.28
Var(X) = 0.6016
E(X | Y=2) = 1.6667
Var(X | Y=2) = 0.4272
Step-by-step explanation:
6(15) + 10b > = 200
90 + 10b > = 200
10b > = 200 - 90
10b > = 110
b > = 110/10
b > = 11
so she can do 15 days of running plus 11 days of biking....which totals 26 days
