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olchik [2.2K]
2 years ago
11

Gus has a fish tank that holds 471047104710 inches^3 3 cubed of water. He is using a cylinder shaped bucket with a radius of 555

inches and a height of 202020 inches to fill the tank. How many times will Gus need to fill the bucket to completely fill the fish tank if he doesn't spill a drop
Mathematics
1 answer:
monitta2 years ago
4 0

Answer:

3 times.

Step-by-step explanation:

Allow me to revise your question for a better understanding.

<em>Gus has a fish tank that holds 4710 inches^3 cubed of water. He is using a cylinder shaped bucket with a radius of 5 inches and a height of 20 inches to fill the tank. How many times will Gus need to fill the bucket to completely fill the fish tank if he doesn't spill a drop. </em>

Here is my answer:

Given:

Fish tank volume: 4710 inches^3

Cylinder shaped bucket :

  • Radius r = 5 inch
  • Height = 20 inches

So we need to find the volume of the Cylinder shaped bucket :

V = πr^{2}h

= 3.14*5^{2} *20 = 1570 inches^3  

From the question we know that Gus uses the bucket to fill in the tank, so the numbers of time he needs to fill the bucket to completely fill the fish tank is:

\frac{Volume of the tank }{Volume of the bucket} = \frac{4710}{1570} =  3 times.

Hope it will find you well.

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Find the eccentricity, b. identify the conic, c. give an equation of the directrix, and d. sketch the conic.
densk [106]

Answer:

a) 10/3  

b) hyperbola

c) x = ± 6/5

Step-by-step explanation:

a) A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:

r=\frac{ep}{1\pm e*cos\theta}

Given the conic equation: r=\frac{12}{3-10cos\theta}

We have to make it to be in the form r=\frac{ep}{1\pm e*cos\theta}:

r=\frac{12}{3-10cos\theta}\\\\multiply\ both\ sides\ by\ \frac{1}{3} \\\\r=\frac{12*\frac{1}{3}}{(3-10cos\theta)*\frac{1}{3}}\\\\r=\frac{12*\frac{1}{3}}{3*\frac{1}{3}-10cos\theta*\frac{1}{3}}\\\\r=\frac{4}{1-\frac{10}{3}cos\theta } \\\\r=\frac{\frac{10}{3}(\frac{6}{5} ) }{1-\frac{10}{3}cos\theta }

Comparing with  r=\frac{ep}{1\pm e*cos\theta}

e = 10/3 = 3.3333, p = 6/5

b) since the eccentricity = 3.33 > 1, it is a hyperbola

c) The equation of the directrix is x = ±p = ± 6/5

6 0
2 years ago
Assuming that a computer has been used to compute a P-value = 0.01635, what can we conclude about the following situation? A sim
Arada [10]

Answer:

Step-by-step explanation:

From the information given, we would write the hypothesis.

For the null hypothesis,

H0 : µ = 70

For the null hypothesis,

Ha : µ > 70

This is a right tailed test because of the symbol of greater than.

The decision rule is to reject the null hypothesis if the level of significance is greater than the p value and accept the null hypothesis if the level of significance is lesser than the p value.

Therefore, since the significance level, 0.05 > p value, 0.01635, then we would reject the null hypothesis. There is enough evidence that the mean speed of all cars is greater than the posted speed limit of 70 mph.

8 0
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Hannah took $50.00 to go shopping and she bought 2 shirts for $17.00 each how change did she have left
Vlad1618 [11]

Answer: Hannah had $16.00 left.

Step-by-step explanation: First, you add $17.00 plus $17.00 or $17.00 times 2 which gives you $34.00. Then, you subtract $50.00 minus $34.00 which gives you $16.00.

4 0
2 years ago
If the test scores of a class of 35 students have a mean of 74.3 and the test scores of another class of 28 students have a mean
STALIN [3.7K]
Let the total sum of the scores of the first class of 35 students be a. The mean is 74.3 .

So 
\frac{a}{35}=74.3\\\\a=35\cdot74.3= 2600.5

Also, let the total sum of the scores of the second class of 28 students be b. The mean is 67.6 .

so 
\frac{b}{28}=67.6\\\\ b=28\cdot67.6= 1892.8



The combined group has 35+28=63 students. The sum of their scores is 

a+b=
2600.5+1892.8=4493.3


Thus, the mean of the combined group is \frac{4493.3}{63}= 71.32

6 0
2 years ago
A commercial jet can fly 868 miles in 2 hours with a tailwind but only 792 miles in 2 hours into a headwind. Find the speed of t
erik [133]

Answer:

The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

Let

x -----> the speed of the wind in miles per hour

y ----> the speed of the jet in still air in miles per hour

we know that

<em>With a tailwind</em>

y+x=\frac{868}{2}

y+x=434 ----> equation A

<em>With a headwind</em>

y-x=\frac{792}{2}

y-x=396 ----> equation B

solve the system of equations A and B by elimination

Adds equation A and equation B

y+x=434\\y-x=396\\------\\y+y=434+396\\2y=830\\y=415

<em>Find the value of x</em>

y+x=434

415+x=434

x=434-415

x=19

therefore

The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph

6 0
2 years ago
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