Answer: 2.845
Step-by-step explanation:
The formula to find the standard deviation is given by :-
, where p is the probability of getting success in each trial and n is the sample size.
Given : Sample size : n=110
The proportion of employees older than 55 and considering retirement : p=0.08
Then, the standard deviation is given by :-
Hence, the standard deviation for the sampling distribution of the sample proportions is 2.845.
Answer:
January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.
Step-by-step explanation:
z-score:
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
January:
The mean daily sales for January was $300 with a standard deviation of $20. On the 15th of January, the shop sold $310 of yogurt. This means, respectively, that . So
February:
The mean daily sales for February was $320 with a standard deviation of $50. On the 15th of February, the shop sold $340 of yogurt. This means, respectively, that . So
January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.
Answer:
<h2>See the explanation.</h2>Step-by-step explanation:
a.
The initial length of the candle is 16 inch. It also given that, it burns with a constant rate of 0.8 inch per hour.
After one hour since the candle was lit, the length of the candle will be (16 - 0.8) = 15.2 inch.
After two hour since the candle was lit, the length of the candle will be (15.2 - 0.8) = 14.4 inch. The length of the candle after two hours can also be represented by {16 - 2(0.8)}.
Hence, the length of the candle after t hours when it was lit can be represented by the function, .
at t = 20.
b.
The domain of the function is 0 to 20.
c.
The range is 0 to 16.