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sladkih [1.3K]
1 year ago
6

If a buyer purchases 25% of a lot in the spring and then purchases 50% more later in the fall, what percentage of the lot is sti

ll available for purchase?
Mathematics
1 answer:
blsea [12.9K]1 year ago
4 0
Let
T--------> the total of the lot

we know that
a buyer purchase=0.25T+0.50T------> 0.75T

<span> lot still available for purchase=T-[0.75T]-----> 0.25T
T----------> 100%
0.25T----> x
x=0.25T*100/T------> x=25%

the answer is
25%</span>
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Sue played four games of golf.
alisha [4.7K]

Answer:

Sue's scores for the four games in ascending order are: 97, 98, 98, 107

Step-by-step explanation:

Her modal score was 98.  The mode is found by using the number that appears most often.  This means that 98 has to appear at least two times out of the four scores.

Her range was 10.  The range is found by taking the highest score and subtracting it from the lowest score.  The highest score had to be greater than 98 and the lowest score had to be less than 98 since we know the mode was 98.

Her mean score was 100.  This mean is found by adding all the numbers together and then dividing by the total numbers listed.  Adding the four scores together and dividing by 4 will equal 100.

Used guess and test:

Highest Number, 98, 98, Lowest Number

107 - 97 = 10 (meets range requirement)

97 + 98 + 98 + 107 = 400

400/4 = 100 (meets the mean requirement)

7 0
2 years ago
Read 2 more answers
There is a harvest festival each year on the planet Bozone. During that time, most of the Bozone residents sit down to rejoice a
Oliga [24]

Answer:

The price would be decreased by 18 bozats

Step-by-step explanation:

The following information is given in the question

x = number of kilograms of snig sold

P = Price per kilogram

And, the equation is

p = 300 - 18x

Now if an extra kilogram is sold so it should be x+1

Now the new price is

New price = 300 - 18(x + 1)

= 300 - 18x - 18

Therefore the price would be decreased by 18 bozats

8 0
1 year ago
Read 2 more answers
The product of two ratio rational numbers is 48/5. If one of the rational number is 66/7, find the other rational number.
goldenfox [79]
Let x = the other rational number.

x(66/7) = (48/5)

Solve for x to find your answer.
3 0
1 year ago
Which rational number is one tick mark to the right of Negative 6 Over 4 on the number line below?
murzikaleks [220]

Answer:

The number line is missing, but as we are know that the number marked in the number line is -6/4, i will guess that the ticks are spearated by fourts (the distance between each tick is 1/4).

Now, for the number at the right of -6/4, we should add the distance for one tick, this means that the number at the right is:

-6/4 + 1/4 = -5/4.

Now i will give some other examples:

Now, if the distance between ticks is 2/4, then the number at the right will be:

-6/4 + 2/4 = -4/4 = -1

Now, if the distance between ticks is 3/4, the the number at the right will be:

-6/4 + 3/4 = -3/4.

4 0
1 year ago
Every day, Jorge buys a lottery ticket. Each ticket has a probability of of winning a prize. After six days, what is the probabi
Romashka [77]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Every day, Jorge buys a lottery ticket. Each ticket has a 0.16 probability of winning a prize. After six days, what is the probability that Jorge has won at least one prize? Round your answer to four decimal places.

Answer:

The probability that Jorge has won at least one prize after six days is

P(at least 1 win) = 0.6487

Step-by-step explanation:

Every day, Jorge buys a lottery ticket which has a 0.16 chance of winning a prize.

We want to find out the probability that Jorge has won at least one prize after six days.

P(at least 1 win) = 1 - P(not winning for 6 days)

We know that the probability of winning is 0.16 then the probability of not winning is

P(not winning) = 1 - 0.16 = 0.84

For 6 days,

P(not winning for 6 days) = 0.84×0.84×0.84×0.84×0.84×0.84

P(not winning for 6 days) = 0.84⁶

P(not winning for 6 days) = 0.3513

Finally,

P(at least 1 win) = 1 - P(not winning for 6 days)

P(at least 1 win) = 1 - 0.3513

P(at least 1 win) = 0.6487

6 0
2 years ago
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