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2 years ago

If a polygon is a regular pentagon, then it has 5 sides.

Mathematics

2 answers:

Aleksandr [31]2 years ago

8 0

Answer: The converse is "If a polygon has 5 sides, then it is a regular pentagon" and it is FALSE.

Step-by-step explanation: We are given to state the converse of the following conditional statement and to determine whether it is true or false :

"If a polygon is a regular pentagon, then it has 5 sides".

We know that

the converse of a conditional statement "p ⇒ q" is given by "q ⇒ p".

Therefore, the CONVERSE of given conditional statement is

"If a polygon has 5 sides, then it is a regular pentagon".

The converse is not true, because if a polygon has 5 sides, then it is a pentagon, not necessarily a regular pentagon.

Thus, the converse is "If a polygon has 5 sides, then it is a regular pentagon" and it is FALSE.

mina [271]2 years ago

3 0

If a polygon has 5 sides, then it is a regular pentagon
False: regular pentagon = equiangular. There are pentagons that have 5 sides that are not equiangular

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dmitriy555 [2]

Point (-5,-3) Slope -2
Y - y1 = m (x - x1)
y + 3 = -2 (x + 5)
y + 3 = -2x - 10
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The line will also go through the point (0, -13)

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2 years ago

For the data that are shown on the graph below, which best describes within which range of x-values extrapolation occurs? On a g

aalyn [17]

Given:

On a graph, points are at (0, 15), (1, 17), (3, 18), (4, 20) and (6, 22).

To find:

The range of x-values extrapolation occurs.

Solution:

Consider the below figure attached with this question.

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2 years ago

If ray JG is an angle bisector of ∠FJH, find m∠FJH.

miss Akunina [59]

Answer:

m∠FJH=60°

Step-by-step explanation:

The complete question is

JG bisects FJH, FJG= (2x + 4)° and GJH = (3x -9)°

What is FJH

we know that

m∠FJH=m∠FJG+m∠GJH -----> equation A

If ray JG is an angle bisector of ∠FJH

then

m∠FJG=m∠GJH -----> equation B

substitute the given values in equation B and solve for x

(2x + 4)°=(3x -9)°

3x-2x=4+9

x=13

Find the measure of angle FJH

m∠FJH=(2x + 4)°+(3x -9)°

substitute the value of x

m∠FJH=(2(13) + 4)°+(3(13) -9)°

m∠FJH=(30)°+(30)°

m∠FJH=60°

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2 years ago

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Korvikt [17]

Answer:

4/9

Step-by-step explanation:

The scale factor for the linear dimensions of the ball bearings will be the cube root of the volume scale factor:

k = ∛(1.6/5.4) = 2/3

Then the scale factor for the areas will be the square of this scale factor:

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_____

The area is the product of two linear dimensions, so its scale factor is the product of the linear dimension scale factors. That is, the scale factor for area is the square of the linear dimension scale factor.

Similarly, volume is the product of three linear dimensions, so its scale factor is the cube of the linear dimension scale factor.

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vovangra [49]

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