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2 years ago

If a polygon is a regular pentagon, then it has 5 sides.

Mathematics

2 answers:

Aleksandr [31]2 years ago

8 0

Answer: The converse is "If a polygon has 5 sides, then it is a regular pentagon" and it is FALSE.

Step-by-step explanation: We are given to state the converse of the following conditional statement and to determine whether it is true or false :

"If a polygon is a regular pentagon, then it has 5 sides".

We know that

the converse of a conditional statement "p ⇒ q" is given by "q ⇒ p".

Therefore, the CONVERSE of given conditional statement is

"If a polygon has 5 sides, then it is a regular pentagon".

The converse is not true, because if a polygon has 5 sides, then it is a pentagon, not necessarily a regular pentagon.

Thus, the converse is "If a polygon has 5 sides, then it is a regular pentagon" and it is FALSE.

mina [271]2 years ago

3 0

If a polygon has 5 sides, then it is a regular pentagon
False: regular pentagon = equiangular. There are pentagons that have 5 sides that are not equiangular

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30,45,x,100; The median is 51

Alex Ar [27]

To solve for x, you must first understand how the median was calculated out of the given set of numbers. Without looking at the given median value, we can see that we cannot get the median by process of elimination since there are an even amount of numbers in this particular set. Therefore, we must average the two closest values to what should be the median.

In this case, the values are "45" and "x". If we pretend that we know the value of the variable "x" (for example we will pretend that x is 55), then we should have an equation that looks like this: (45+55) ÷ 2 = [median]. What this equation is doing is adding the two closest values to the median (45 and 55) and dividing it by 2, the number of values we are averaging. Now we can solve this equation and simplify it to 100 ÷ 2 which is 50, our median.

So if they give us the median instead of the x value, then we can rewrite the equation to fit your request: (45+x) ÷ 2 = 51. Now we can solve for x:

1. Multiply by 2
(45+x) = 102

2. Subtract 45
x = 57

The x value for your question is 57.

3 0

2 years ago

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The parabola y=x^2y=x 2 y, equals, x, start superscript, 2, end superscript is reflected across the xxx-axis and then scaled ver

kramer

ANSWER

The equation of the new parabola is

$y = - 5 {x}^{2}$

EXPLANATION

The given parabola has equation:

$y = {x}^{2}$

If this parabola is reflected in the x-axis, its equation becomes :

$y = - {x}^{2}$

When this parabola is scaled vertically by a factor of 5, the equation becomes,

$y = - 5 {x}^{2}$

5 0

2 years ago

What is 63.4 divided by 20

Zanzabum

317 is the answer you are looking for.

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2 years ago

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Line jk passes through points j(-4,-5) and k(-6,3 if the equation of the lines is written in slope-intercept form,y=my+b what is

lidiya [134]

Written in 2-point form, the equation of the line is
y = (y2-y1)/(x2-x1)·(x-x1) +y1
y = (3-(-5))/(-6-(-4))·(x-(-4)) + (-5)
y = 8/-2·(x +4) - 5
y = -4x -21

The value of b is -21.

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2 years ago

Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

lys-0071 [83]

<em>Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work. </em>

<em>But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.</em>

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

$2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$

Lets divide the expression by $2x^2\:-\:3x\:+\:1$

Solution Steps:

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}$

Factorizing

$2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}$

Factorizing

$2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}$

$\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2$

$x^2+5x-2$

Thus,

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2$

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Keywords: expression, division

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1 year ago

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