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2 years ago

Lana draws a triangle( LMN) on the coordinate plane. What is the perimeter of the triangle( LMN)? Round to the nearest unit.

Mathematics

1 answer:

Dmitriy789 [7]2 years ago

8 0

Answer:

Step-by-step explanation:

The longest side is 12.

The two other sides of the triangle= $\sqrt{3 squared+6 squared}$ =(9+36)square rooted=45 square rooted is about 6.7.

6.7*2=13.4

13.4+12=25.4

25.4 rounded to the nearest unit is 25.

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The maximum recommended slope of wheelchair ramp is 1/12. A business installs a wheelchair ramp that rises 22inches over a horiz

Olin [163]

Given parameters:

Recommend wheelchari ramp slope = $\frac{1}{12}$

Rise of the new wheel chair ramp = 22 inches

Horizontal length = 24feet

Unknown:

Is the ramp steeper than the recommended = ?

Slope is the ratio of rise to the horizontal distance covered

Mathematically;

Slope = $\frac{Rise}{horizontal distance}$

Slope of the wheel chair ramp;

covert 24 feet to inches;

1 foot = 12 inches

24 feet = 24 x `12 = 288inches

Slope = $\frac{22}{288 }$ = $\frac{11}{144}$

The two slopes being compared are;

$\frac{1}{12}$ and $\frac{11}{144}$

The steeper of the first one 1/12. It has a higher slope compared to the second one.

4 0

2 years ago

A researcher found a study relating the value of a car, y, to the age of the car, x. When researchers looked at the association

vredina [299]

Answer: c) About 16% of the variation in value of the car is explained by a linear relationship with the age of the car.

e) The correlation coefficient, r, is 0.397.

Step-by-step explanation:

Given that:

Coefficient of determination (r²) between two variables, age of car (x) and value of car (y) = 0.158

Correlation of determination (r²) of 0.158 = (0.158 × 100% = 15.8% of the variation between the two variables can be explained by the regression line). Hence, about 16% of the variation between age and value of car can be explained by the linear relationship.

Coefficient of correlation (r) = sqrt(r²) = sqrt(0.158) = 0.397

8 0

2 years ago

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

2 years ago

A chess player moves a knight from the location (3, 2) to (5, 1) on a chessboard. If the bottom-left square is labeled (1, 1), t

iragen [17]

We have to find how the chess player can move a knight from one location to another.
Also we have to remember that the bottom - left square is labelled ( 1 , 1 ).
First he wants to move a knight from ( 3 , 2 ) to ( 5 , 1 ).
Answer: 2 squares left, 1 square down.
Then he wants to move it from ( 5 , 1 ) to ( 6 , 3 ).
Answer: 2 squares right, 2 squares up, 1 square left.

5 0

2 years ago

Read 2 more answers

Find the area of a regular polygon

Dimas [21]

Answer:

(N-2)x180=sum of interior angles

So (5-2)x180=540

Divided by number of sides=540/4=108... then each angle is 108 divide to triangles ..so they will have 2 angles =54 2 sides =4 the last angle =72 ."of the triangle " area of triangle =1/2xsxsxsin(side in

between)

So 1/2x4x4xsin(72)= then multiply it by 5 as u will have 5 triangles .. so it will be 190.2(probably i tried)

Step-by-step explanation:

4 0

2 years ago