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Anit [1.1K]
2 years ago
7

Nadiya determines that there are no fractions equivalent to 2/10 with a denominator greater than 10, but less than 20, that have

a whole number numerator and denominator. Is Nadiya correct?
Yes, Nadiya is correct. By multiplying the numerator and denominator by 2, the first fraction equivalent to 2/10 is 4/20.

Yes, Nadiya is correct. By multiplying the whole fraction by any whole number, each equivalent fraction will continue to have a denominator of 10.

No, Nadiya is incorrect. She could multiply both the numerator and denominator of the unit fraction equivalent to 2/10 by 3 and arrive at the equivalent fraction 3/15.

No, Nadiya is incorrect. She could add any number between 1 and 8 to the numerator and denominator and arrive at an equivalent fraction with a denominator greater than 10 but less than 20.

Mathematics
2 answers:
frosja888 [35]2 years ago
8 0

Answer:

Yes, Nadiya is correct. By multiplying the numerator and denominator by 2, the first fraction equivalent to 2/10 is 4/20.

Step-by-step explanation:

To find a fraction equivalent to 2/10, we need to multiply (or divide) the numerator and denominator by the same nonzero whole number.

As we need an equivalent fraction with a denominator greater than 10, we will need to multiply and not divide.

The first nonzero whole number we have is 1. If we multiply the numerator and denominator by 1, we get 2/10. Obviously, 2/10 is equivalent to 2/10 but the denominator is not greater than 10, so it doesn't help us.

The next whole number is 2. When we multiply the numerator and denominator by 2, we get 4/20. The denominator is not less than 20.

If we keep going, we will get 6/30, 8/40 and so on.  

Therefore, Nadiya is correct.

The correct answer is the first one.

vampirchik [111]2 years ago
3 0

Answer: It is C

Step-by-step explanation: I literally just took the test bruhh

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A website advertises job openings on its website, but job seekers have to pay to access the list of job openings. The website re
nataly862011 [7]

Answer:

The 90% confidence interval would be given by (57.006;62.994)  

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X=60 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=10 represent the population standard deviation  

n=30 represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma=10)

The sample mean \bar X is distributed on this way:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})  

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.90=0.1,\alpha/2 =0.05 and z_\alpha/2=1.64  

Using the normal standard table, excel or a calculator we see that:  

z_{\alpha/2}=1.64

Since we have all the values we can replace:

60 - 1.64\frac{10}{\sqrt{30}}=57.006  

60 + 1.64\frac{10}{\sqrt{30}}=62.994  

So on this case the 90% confidence interval would be given by (57.006;62.994)  

5 0
2 years ago
Ed bought 3 liters of water, 2,750 milliliters of sports drinks, and 2.25 liters of juice. For numbers 4a-4e, select True or Fal
skelet666 [1.2K]
3 liters of water=3,000<span>milliliters of water
</span><span>2.25 liters of juice= 2,250milliliters of juice
</span><span>2,750 milliliters of sports drinks,

</span><span>Ed bought 250 milliliters more water than sports drink it is TRUE
</span>Proof 3,000<span>milliliters -2,750milliliters = 250milliliters

</span><span>Ed bought 1.25 liters more water than juice, it is FALSE
</span>proof  3,000<span>milliliters -2,250milliliters = 750milliliters=0.75l

</span><span>Ed bought 50 milliliters more sports drink than juice. it is FALSE
proof </span><span>2,750 -2,250=500milliliters not 50milliliters

</span><span>Ed bought 0.5 liter more of sports drink than juice. it is TRUE
</span>proof <span>2,750 -2,250=500milliliters =0.5l
</span>
<span>Ed bought 75 milliliters more water than juice. it is FALSE
</span>proof 3,000-2,250= 750milliliters (not 5 milliliters)
6 0
1 year ago
Sina played basketball on a rectangular court that was 74 feet by 42 feet. after the game, she walked across the court diagonall
Naddika [18.5K]
the distance Sina walked was 7,240 feet
6 0
1 year ago
Read 2 more answers
Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units. Which statements bes
valentinak56 [21]

Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.

By the definition of rhombus, diagonals meet at right angles.

Implies that PQ = QA

x+2 = 3x - 14

x-3x=-14-2

-2x=-16

2x = 16

dividing by 2 on both sides, we will get,

x =\frac{16}{2}

<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>

The line segment \overrightarrow{PA}=\overrightarrow{PQ}+\overrightarrow{QA}

\overrightarrow{PA}=x+2+3x-14

=4x-12

=4(8)-12 ( since x=8)

=32-12

=20

<h3>∴ \overrightarrow{PA}=20 units</h3>
3 0
1 year ago
The length of a rectangle is 24 units. can the perimeter x of the rectangle be 60 units when its width y is 11 units? (1 point)
Sergio [31]

Okay, well we start out with the equation P=66, where P is perimeter. You should create equations using variables to explain each piece of information you are given. Follow the equations below and see if you can understand how to do another one like this. In this problem, l is length and w is width.


P = 66                               The perimeter is equal to 66

l = 3 + w                           The length of one side is 3 more than the width

2l + 2w = 66                      A rectangle's perimeter is calculated by adding the lengths and widths

2(3 + w) + 2w = 66           Use what you know about length from step 2 to replace the variable in step 3

6 + 2w + 2w = 66              Multiply

6 + 4w = 66                       Add like terms

4w = 60                            Subtract

w = 15                             Divide

l = 3 + w                         Remember step 2?

l = 3 + 15                       Replace the variable using your value for w

l = 18                             Add

And you're done! Always check your work. It helps to create a picture of a rectangle while you're doing these problems as well. As you get used to these problems more and more, you can show more or less work than I've shown, but try to stay true to what the teacher asks of you. Good luck!

8 0
1 year ago
Read 2 more answers
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