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2 years ago

Which could be the function graphed below?

Mathematics

2 answers:

stiv31 [10]2 years ago

3 0

The parent equation of the given graph is $y=\sqrt[n]{x}$

where, n is any even number.

When this function is vertically shifted ( vertical dilation) down in the y- axis,

we get a graph similar to the one given in the question.

For example: $y=\sqrt[2]{x}-2$

The graph of the above function is attached below.

Fed [463]2 years ago

3 0

Try this way:
$f(x)= \sqrt[n]{x} -a,$
where n - even number, a - const.
P.S. one example is in the attachment.

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the scale on a map is stated as 1:250000 two villages are 9 cm apart on the map how far from each other are the two villages in

Karolina [17]

Answer:

22.5 kilometers

Step-by-step explanation:

we know that

The scale drawing is

$1:250,000$

That means

1 unit on a map represent 250,000 units in the actual

1 cm on a map represent 250,000 cm in the actual

1 cm on a map represent 2,500 m in the actual

1 cm on a map represent 2,5 km in the actual

therefore

using proportion

Find out how much represent 9 cm apart on the map

$\frac{1}{2.5}\ \frac{cm}{km}=\frac{9}{x}\ \frac{cm}{km}\\\\x=9(2.5)\\\\x=22.5\ km$

7 0

2 years ago

Jalen inherited a collection of vintage comic books. An appraiser separated the comic

sladkih [1.3K]

Jalen has total 63 comic books.

Step-by-step explanation:

Given,

Total value of comic books = $3135

Let,

Number of $45 comic books = x

Number of $65 comic books = y

According to given statement;

45x+65y=3135 Eqn 1

x=y+33 Eqn 2

Putting value of x from Eqn 2 in Eqn 1

$45(y+33)+65y=3135\\45y+1485+65y=3135\\110y=3135-1485\\110y=1650\\$

Dividing both sides by 110

$\frac{110y}{110}=\frac{1650}{110}\\y=15$

Putting y=15 in Eqn 2

$x=15+33\\x=48$

Total comic books = x+y

Total comic books = 48+15 = 63

Jalen has total 63 comic books.

Keywords: addition, elimination method

Learn more about elimination method at:

#LearnwithBrainly

7 0

2 years ago

A student theater charges $9.50 per ticket. The theater has already sold 70 tickets. Write and solve an inequality that represen

Genrish500 [490]

9.50 times 70 is greater or less than 1000

8 0

2 years ago

Diana sold 336 muffins at the bake sale.Bob sold 287 muffins.Bob estimates that he sold 50 fewer muffins than Diana.how did he e

malfutka [58]

Step-by-step explanation:

Since we have given that

Number of muffins Diana sold at the bake sale = 336

Number of muffins Bob sold at the bake sale = 287

Now, here we are using the method of estimation i.e. rounding the integers to nearest ones.

By estimation, we get

Number of muffins Diana sold at the bake sale = 340

Number of muffins Bob sold at the bake sale = 290

So,

Difference between them is given by

$340-290\\=50$

Hence, Bob sold 50 fewer muffins than Diana.

3 0

2 years ago

Read 2 more answers

A savings and loan association needs information concerning the checking account balances of its local customers. A random sampl

Citrus2011 [14]

Answer:

a) 98% confidence interval for the true mean checking account balance for local customers.

(453.586 , 874.693)

b) 95% confidence interval for the standard deviation.

(214.91 , 441.53)

Step-by-step explanation:

Given a size of sample 'n' =14

given mean of the sample x⁻ = $664.14

standard deviation of the sample 'S' = $297.29.

98% of confidence intervals

$(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-}+ t_{\alpha }\frac{S}{\sqrt{n} } )$

The degrees of freedom γ=n-1 =14-1 =13

t₁₃ = 2.650 at 98% of confidence level of signification.

$(664.14- 2.650\frac{297.29}{\sqrt{14} } , 664.14+ 2.650\frac{297.29}{\sqrt{14} } )$

on calculation, we get

(664.14-210.553 , 664.14+210.553)

(453.586 , 874.693)

98% confidence interval for the true mean checking account balance for local customers.

(453.586 , 874.693)

95% of confidence intervals

$({s\sqrt{\frac{n-1}{X^{2} _{(\frac{\alpha }{2} ,n-1) } } } ,s\sqrt{\frac{n-1}{X^2_{\frac{1-\alpha }{2},n-1 } } } )$

The degrees of freedom γ=n-1 =14-1 =13

X^2_{0.05,13} =22.36 (check table)

X^2_{0.95,13} = 5.892 (check table)

$(297.29. (\sqrt{\frac{14-1}{X^2_{0.05,13} } } ),297.29(\sqrt{\frac{14-1}{X^2_{0.95,13} } } )$

$(297.29. (\sqrt{\frac{14-1}{22.36 } } ),297.29(\sqrt{\frac{14-1}{5.892 } } )$

(214.91 , 441.53)

95% confidence interval for the standard deviation.

(214.91 , 441.53)

7 0

2 years ago