5c+10a=3570
c+a=512
...
a=512-c
so ...
5c + 10(512-c)=3570
What is the question?
I'm assuming it is to find the length and width.
+_= plus or minus
(X+36)
____________
| |
(X) | |
|____________|
X^2+36X-2040<0
X<-36+_(36^2-4*-2040)^(1/2)
-----------------------------------
2
X<-18+_2((591)^(1/2))
This is probably not what you wanted, sorry
Answer:
Multiply by ∛2 and translate the graph to left by 4 units.
Step-by-step explanation:
The initial function given is:
y = -∛(x - 4)
The transformed function is:
y = -∛(2x - 4)
Consider the initial function.
y = -∛(x - 4)
(Represented by Black line in the graph)
Multiply the function by ∛2. The function becomes:
y = -∛(x - 4) × ∛2
y = -∛(2)(x-4)
y = -∛(2x-8)
(Represented by Red line in the graph represents this function)
Translate the graph 4 units to the left by adding 4 to the x component:
y = -∛(2x-8+4)
y= -∛(2x - 4)
(Represented by Blue line in the graph)
Answer:
20.487%
Step-by-step explanation:
divide the second number by the first. then do one minus that number
Car value at the time of purchase $15, 250 (2012)
Rate of depreciation 7.5%
1) y = 15250 ( 1- 0.075)^x
y = 15250 (0.925)^x (x tis the number of years that passed since purchase)
2) y = 15250 * ( 0.925)^8 = 8173.42