For this problem, I think there is no need for the details of 12 inches width and 4 inches length. This is because an equation is already given. It was clearly specified that A as a function of θ represents the area of the opening. Then, we are asked to find exactly that: the area of opening. Moreover, the value of θ was also given. Therefore, I am quite sure that the initial details given are for the purpose of red herring only.
So, all we have to do is substitute θ=45° to the function given.
A = 16 sin 45° ⋅ (cos 45° + 1)
The angle 45° is a special angle in trigonometry. So, it would be easy to remember trigonometric functions of this angle. Sine of 45° is equal to √2/2 while cosine of 45° is also √2/2.
A = 16(√2/2) ⋅ (√2/2 + 1)
A = 8+8√2
A = 19.31 square inches
Answer:
A and E are correct option.
Step-by-step explanation:
We are given two triangle congruent.
If two triangles are congruent then their corresponding sides and angles are equal.
In ΔTUV ≅ ΔWXY
Now we write all the congruent sides and angles
- ∠T=∠W
- ∠U=∠X
- ∠V=∠Y
- TU≅WX
- UV≅XY
- TV≅WY
Now we see all the given option.
∠Y=∠V (TRUE, Congruent part of congruence triangles)
∠W=∠T (TRUE, Congruent part of congruence triangles)
Thus, A and E are correct option.
<span>The control box’s dimensions are 30 inches by 25 inches. Therefore, the perimeter of the box is 30 inches + 25 inches + 30 inches + 25 inches = 110 inches. There are 12 inches per foot. 12 goes into 110 nine times, with two inches left over. Therefore, 9 feet and 2 inches of weatherstripping is needed.</span>
If we let
x as the distance traveled by the boat
y as the distance between the boat and the lighthouse.
Then, we have:
tan 18°33' = 200 / (x + y)
and
tan 51°33' = 200 / y
Solving for y in the second equation:
y = 200 / tan 51°33'
Rearranging the first equation and substituting y
x = 200 / tan 18°33' - 200 / tan 55°33'
x = 458.81 ft
Therefore, the boat traveled 458.81 ft before it stopped.
