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2 years ago

Why wouldn't the man stand in line to step on the scale ? answer ?

1 answer:

7 0

The man would not stand in line to step on the scale because he already has a scale at home. There is no need for him to step in line if he already has a scale.

You might be interested in

Which statements are true about the graph of y s 3x + 1 and y 2 -x + 2? Check all that apply.

Varvara68 [4.7K]

Let's go through all the options one at a time and look for the correct ones

Option 1: The slope of one boundary line is 2

We have 2 equations of lines, where the coefficients of are 3 and -1 respectively

because the coefficient of x denotes the slope of a line, we know that the lines have the slope 3 and -1, not 2

Hence, this option is Incorrect

Option 2: Both boundary lines are solid

In order for the boundary lines to be solid, the inequality must have an 'equal to', like ≤ (less than or equal to) or ≥ (greater than or equal to)

we can see that that's the case in our case and hence, this option is Correct

Option 3: A solution to the system is (1, 3)

To confirm this, we'll plug these coordinates into the given inequalities and see if it stands correct

y ≤ 3x + 1

3 ≤ 3(1) + 1

3 ≤ 4 which is correct because 3 is less than 4

Second equation:

y ≥ 2 - x

3 ≥ 2 - 1

3 ≥ 1

Which is also true because 3 is greater than 1

Now, we can say that (1 , 3) is a solution to the system because it satisfies both the equations and is Correct

Option 4: Both inequalities are shaded below the boundary lines

For an inequality to be shaded below the boundary line, it must have the ≤ inequality (in case of solid line) and < inequality (in case of dotted line)

because the second inequality listed includes the ≥ inequality, which was not mentioned above, it won't be shaded below

another way to think about it is that any 'greater than' inequality will shade everything above the line and the 'lesser than' inequality will shade below the line

which means that this option is Incorrect

Option 5: The boundary lines intersect

In order for the boundary lines to intersect, they must have have different slopes.

as we mentioned in the explanation of the first option, that the slopes of the lines is 3 and -1, which are different slopes

Therefore, this option is Correct

5 0

2 years ago

Read 2 more answers

Lucy wants to have a fun-filled day without spending too much money. The local zoo charges a $25 entry fee and a parking fee of

ehidna [41]

Answer:

The required system of equations is,

$y=25+x$

$y=20+2x$ .

Step-by-step explanation:

Let the number of hours spent by Lucy = x

It is given that,

Local zoo charges initial fee $25 and per hour fee $1.

So, the equation representing the cost if Lucy stays 'x' hours is,

$y=25+x$ in dollars.

Also, Local citcus charges initial fee $20 and per hour fee $2.

So, the equation representing the cost if Lucy stays 'x' hours is,

$y=20+2x$ in dollars.

Since, the objective function for the situation is to 'minimize the cost'.

So, upon solving the equations, we will get the minimum value as,

25+x = 20+2x

i.e. x= 5

Thus,

$y=25+x$ implies $y=25+5$ i.e. y= $30

$y=20+2x$ implies $y=20+2\times 5$ i.e. $y=20+10$ i.e. y= $30

Thus, the minimum value is $30.

The required system of equations is,

$y=25+x$

$y=20+2x$ .

8 0

2 years ago

The length of a picture frame is 6 inches more than the width. For what values of x is the perimeter of the picture frame greate

aniked [119]

Answer:

x > 36 in

Step-by-step explanation:

Let x = the width of the picture frame.

Then x + 6 = the length of the frame.

The formula for the perimeter P of a rectangle is'

P = 2l + 2w.

So, the condition is

2l + 2w > 156

2(x + 6) + 2x > 156 Distribute the 2

2x + 12 + 2x > 156 Combine like terms

4x + 12 > 156 Subtract 12 from each side

4x > 144 Divide each side by 4

x > 36

The perimeter of the picture frame will be greater than 156 in if x > 36 in.

5 0

2 years ago

Using the U- Substitution u=sqrt(2x), integral form 2-8 dx/ sqrt(2x) + 1 is equivalent to ...

AleksAgata [21]

We will use u-substitute: $u= \sqrt{2x} , \frac{du}{dx}= \frac{1}{ \sqrt{2x} }= \frac{1}{u}$ Then for substitution:dx=u du. and integral becomes: $\int { \frac{u}{u+1} } \, du = \int { \frac{u+1-1}{u+1} } \, du= \int{1} \, du- \int { \frac{1}{u-1} } \, dx$ =u-ln(u+1)= $\sqrt{2x}-ln( \sqrt{2x}+1)$ . Now we will change the values of limits: $\sqrt{16}-ln( \sqrt{16}+1)-( \sqrt{4}-ln( \sqrt{4}+1))$ =4-ln(5)-2+ln(3)=2+ln(0,6)=2-0.51=1.49

8 0

2 years ago

Emily is thinking of a number, which she calls n. She finds 1/4 of the number and then subtracts 3. Write an expression to repre

Ludmilka [50]

Answer:

1/4n-3

Step-by-step explanation:

3 0

2 years ago