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myrzilka [38]
2 years ago
14

300-297+294-291+288-285+...+6-3

Mathematics
1 answer:
vladimir2022 [97]2 years ago
7 0
300 - 297 = 3

294 - 291 = 3

288 - 285 = 3

So, that is a sequence of sums of number 3: 3 + 3 + 3 + .... + 3

How may times will the number 3 be added?

Note that 300 is reduced in 6 units each time => 300 / 6 = 50 => 3 will be added 50 times.

=> 50 * 3 = 150

Answer: 150
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Mr. Cruz fills a 3-gallon water cooler for a family picnic. He brings plastic cups that each hold 12 fluid ounces of water. How
oksian1 [2.3K]

One gallon is equivalent to 128 fluid ounces

3 gallons is equivalent to 3*128 fluid ounces

= 384 fluid ounces

One plastic cup can hold 12 guide ounces

So cups needed will be 384/12

32 cups

8 0
1 year ago
What is the recursive rule for an=2n+11?
Dmitrij [34]
The answer is B 
a1= 13;an-1+2

6 0
2 years ago
Read 2 more answers
If f(1) = 0 what are all the roots of the function f(x)=x^3+3x^2-x-3 use the remainder theorem.
ArbitrLikvidat [17]

Solution:

As we are given that f(1) = 0 .

It mean that (x-1) is one of the factor of the given equation.

Remainder theorem can be applied as below:

\frac{(x^3+3x^2-x-3)}{(x-1)}=\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}\\ \\\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}=\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)} \\\\\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)}=\frac{(x^2+4x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+4x+3)(x-1)}{(x-1)} =\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  =\frac{(x-1)(x+3)(x+1)}{(x-1)}

Hence the factors are (x-1),(x+3) and (x+1).

Hence the correct option is B.

5 0
2 years ago
Read 2 more answers
A bacon cheeseburger at a popular fast food restaurant contains 2,070mg of sodium, which is 86% of the recommended daily amount.
svp [43]
2,070mg 86%
— = —
? mg 100%

Cross multiply (2,070 X 100) which equals 207,000

Then divide 207,000 by 86 which equals
2,406.976

Then you round so you get 2,407


The Answer is 2,407 milligrams
5 0
2 years ago
Monica has a bag of marbles. There are 4 red marbles and 7 blue marbles and 5 yellow marbles in a bag. Monica will randomly pick
natima [27]

Answer:

\frac{7}{64}\approx 0.11

Step-by-step explanation:

We have been given that there are 4 red marbles and 7 blue marbles and 5 yellow marbles in a bag. Monica will randomly pick two marbles out of the bag replacing the first marble before picking the second marble.

Since Monica will replace the first marble before picking the second marble, therefore, probability of both events will be independent and probability of occurring one event will not affect the probability of second event's occurring.          

Since the probability of two independent compound events is always the product of probabilities of both events.

P(\text{A and B})=P(A)*P(B)

Now let us find probability of picking a red marble out of 16 (4+7+5) marbles.

P(Red)=\frac{\text{Total red marbles}}{\text{Total marbles}}

P(Red)=\frac{4}{16}

Probability of picking blue ball out of 16 (4+7+5) marbles:

P(Blue)=\frac{\text{Total blue marbles}}{\text{Total marbles}}

P(Blue)=\frac{7}{16}

Now let us find probability of Monica picking a red and then a blue marble.

P(\text{Red and Blue})=\frac{4}{16}\times \frac{7}{16}

P(\text{Red and Blue})=\frac{1}{4}\times \frac{7}{16}

P(\text{Red and Blue})=\frac{7}{4*16}

P(\text{Red and Blue})=\frac{7}{64}

P(\text{Red and Blue})=0.109375\approx 0.11

Therefore, the probability of picking a red and then blue marble is \frac{7}{64}\approx 0.11.  

7 0
2 years ago
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