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Aneli [31]
2 years ago
5

Tim installs 50 square feet of his floor in 45 minutes. At this rate, how long does it take him to install 495 square feet? (Ple

ase show ur work)
Mathematics
2 answers:
Alenkinab [10]2 years ago
5 0

Answer:

445.5min=595²ft

Step-by-step explanation:

y=0.9x

y=0.9*495

y=445.5

Nuetrik [128]2 years ago
4 0

Answer:

445.5 minutes

Step-by-step explanation:

Tim installs 50 square feet of his floor in 45 minute . Let us calculate it as a rate

Since he installs 50 ft² of his floor in 45 minute. How many square ft will he install in 1 minutes

50 ft² → 45 minutes

? →         1 minute

he will install 50/45 ft² per minute

50/45 ft² →  1 minute

495 ft² → ? minute

cross multiply

495 × 45/50

22275 /50

445.5 minutes

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a water tank holds 24,000 gallons how many hours will it take for two thirds of the water to be used if the water is used at an
melomori [17]
In this question there are several important information's worth noting.Based on these information's the answer can be easily found. It is given that the total capacity of the tank is 24000 gallons. in 24 hours or in 1 day the amount of water used is 650 gallons. The question requires us to find the time it will take to use 2/3 rd of the water in the tank.
then
2/3 rd water in respect to total water in tank = (2/3) * 24000
                                                                       = 16000
So 2/3 rd water of full tank is equivalent to 16000 gallons.
Now
650 gallons of water is used in = 24 hours
So
16000 gallons of water will be used in = (24/650) * 16000
                                                             = 590.77 hours
So it will take 590.77 hours to consume 2/3rd of the total water present in the tank.
6 0
2 years ago
We want to evaluate dog owners’ reactions to a new dog food product formulation that contains more vegetables. A promotional boo
Arada [10]

Answer:

Inherently asymmetrical casual relationship.

Step-by-step explanation:

The dog owners are given free dog food samples which contain new vegetables. These samples are given to them by organizing booths at the dog events. The reaction of the dog owners is observed towards this new dog food. This an example of inherently asymmetrical relationship.

6 0
2 years ago
Three couples and two single individuals have been invited to an investment seminar and have agreed to attend. Suppose the proba
Maksim231197 [3]

Answer:

(a) Probability mass function

P(X=0) = 0.0602

P(X=1) = 0.0908

P(X=2) = 0.1704

P(X=3) = 0.2055

P(X=4) = 0.1285

P(X=5) = 0.1550

P(X=6) = 0.1427

P(X=7) = 0.0390

P(X=8) = 0.0147

NOTE: the sum of the probabilities gives 1.0068 for rounding errors. It can be divided by 1.0068 to get the adjusted values.

(b) Cumulative distribution function of X

F(X=0) = 0.0602

F(X=1) = 0.1510

F(X=2) = 0.3214

F(X=3) = 0.5269

F(X=4) = 0.6554

F(X=5) = 0.8104

F(X=6) = 0.9531

F(X=7) = 0.9921

F(X=8) = 1.0068

Step-by-step explanation:

Let X be the number of people who arrive late to the seminar, we can assess that X can take values from 0 (everybody on time) to 8 (everybody late).

<u>For X=0</u>

This happens when every couple and the singles are on time (ot).

P(X=0)=P(\#1=ot)*P(\#2=ot)*P(\#3=ot)*P(\#4=ot)*P(\#5=ot)\\\\P(X=0)=(1-0.43)^{5}=0.57^5= 0.0602

<u>For X=1</u>

This happens when only one single arrives late. It can be #4 or #5. As the probabilities are the same (P(#4=late)=P(#5=late)), we can multiply by 2 the former probability:

P(X=1) = P(\#4=late)+P(\#5=late)=2*P(\#4=late)\\\\P(X=1) = 2*P(\#1=ot)*P(\#2=ot)*P(\#3=ot)*P(\#4=late)*P(\#5=ot)\\\\P(X=1) = 2*0.57*0.57*0.57*0.43*0.57\\\\P(X=1) = 2*0.57^4*0.43=2*0.0454=0.0908

<u>For X=2</u>

This happens when

1) Only one of the three couples is late, and the others cooples and singles are on time.

2) When both singles are late , and the couples are on time.

P(X=2)=3*(P(\#1=l)*P(\#2=ot)*P(\#3=ot)*P(\#4=ot)*P(\#5=ot))+P(\#1=ot)*P(\#2=ot)*P(\#3=ot)*P(\#4=l)*P(\#5=l)\\\\P(X=2)=3*(0.43*0.57^4)+(0.43^2*0.57^3)=0.1362+0.0342=0.1704

<u>For X=3</u>

This happens when

1) Only one couple (3 posibilities) and one single are late (2 posibilities). This means there are 3*2=6 combinations of this.

P(X=3)=6*(P(\#1=l)*P(\#2=ot)*P(\#3=ot)*P(\#4=l)*P(\#5=ot))\\\\P(X=3)=6*(0.43^2*0.57^3)=6*0.342=0.2055

<u>For X=4</u>

This happens when

1) Only two couples are late. There are 3 combinations of these.

2) Only one couple and both singles are late. Only one combination of these situation.

P(X=4)=3*(P(\#1=l)*P(\#2=l)*P(\#3=ot)*P(\#4=ot)*P(\#5=ot))+P(\#1=l)*P(\#2=ot)*P(\#3=ot)*P(\#4=l)*P(\#5=l)\\\\P(X=4)=3*(0.43^2*0.57^3)+(0.43^3*0.57^2)\\\\P(X=4)=3*0.0342+ 0.0258=0.1027+0.0258=0.1285

<u>For X=5</u>

This happens when

1) Only two couples (3 combinations) and one single are late (2 combinations). There are 6 combinations.

P(X=6)=6*(P(\#1=l)*P(\#2=l)*P(\#3=ot)*P(\#4=l)*P(\#5=ot))\\\\P(X=6)=6*(0.43^3*0.57^2)=6*0.0258=0.1550

<u>For X=6</u>

This happens when

1) Only the three couples are late (1 combination)

2) Only two couples (3 combinations) and one single (2 combinations) are late

P(X=6)=P(\#1=l)*P(\#2=l)*P(\#3=l)*P(\#4=ot)*P(\#5=ot)+6*(P(\#1=l)*P(\#2=l)*P(\#3=ot)*P(\#4=l)*P(\#5=ot))\\\\P(X=6)=(0.43^3*0.57^2)+6*(0.43^4*0.57)\\\\P(X=6)=0.0258+6*0.0195=0.0258+0.1169=0.1427

<u>For X=7</u>

This happens when

1) Only one of the singles is on time (2 combinations)

P(X=7)=2*P(\#1=l)*P(\#2=l)*P(\#3=l)*P(\#4=l)*P(\#5=ot)\\\\P(X=7)=2*0.43^4*0.57=0.0390

<u>For X=8</u>

This happens when everybody is late

P(X=8)=P(\#1=l)*P(\#2=l)*P(\#3=l)*P(\#4=l)*P(\#5=l)\\\\P(X=8) = 0.43^5=0.0147

8 0
2 years ago
A craft vendor must sell at least $300 worth of merchandise to make a profit. Scarves sell for $10 each and hats sell for $20 ea
valina [46]
There is a missing graph in the problem given. However, we can simply solve the equation using the given data.

Items to be sold: scarves and hats. Minimum of 20 items sold in all.
Scarves sell for 10 each and hats sell for 20 each. Must sell at least 300 worth of merchandise to make profit. 

Let s represent scarves and h represent hats.

10s + 20h <u>></u> 300
s + h <u>></u> 20

We use inequality because the problem states "at least". 

s + h = 20
10s + 20h = 300

s = 20 - h
10(20-h) + 20h = 300
200 - 10h + 20h = 300
10h = 300 - 200
10h = 100
h = 100/10
h = 10

s = 20 - h
s = 20 - 10
s = 10

s + h <u>></u> 20
10 + 10 <u>></u> 20

10s + 20h <u>></u> 300
10(10) + 20(10) <u>></u> 300
100 + 200 <u>></u> 300

7 0
2 years ago
Read 2 more answers
Use the distributive property to solve the equation 4x/5-x=x/10-9/2
Oksana_A [137]

Answer:

\Huge\boxed {x = 15}

Step-by-step explanation:

⟾Collect like terms

  • 8x - 10x = x - 45

⟾Move the variable to the left

  • - 2x = x - 45

⟾Collect like terms again

  • - 2x - x = - 45

⟾Divide both sides by -3

  • - 3x = - 45

⟾ x = 45 ÷ 3

  • x = 15.

Hope it's helps you

4 0
2 years ago
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