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vesna_86 [32]
2 years ago
15

The yearbook staff enlarges a picture with a length of 5 inches and a width of 7

Mathematics
2 answers:
Pepsi [2]2 years ago
6 0

present dimensions = 5*7

dimensions after scaling with factor 3 = 15*21

dimensions after reducing by scale factor 0.5 = 7.5*10.5

area of rectangle = length * breadth

so area of yearbook = 7.5*10.5 = 78.75

because, 78.75<80

so, the yearbook will fit in area of 80 inches^2

lapo4ka [179]2 years ago
5 0
I believe yes, the area of the picture is 78.75 square inches. hope this helps you
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Maggie brought $10 to the candy store she will buy a certain amount of fudge 1 pound cost to 2.30 if p represents the money magg
xxTIMURxx [149]

Question is Incomplete. Complete question is given below;

Maggie brought $10 to the candy store. She will buy a certain amount of fudge. One pound of fudge costs $2.30.  If p represents the amount of fudge, in pounds, Maggie buys, which expression represents the money Maggie has left after visiting the candy store?

Answer:

The expression that represent the money Maggie has left after visiting the candy store is (10-2.3p)

Step-by-step explanation:

Given:

Money Maggie brought at store = $10

Cost of 1 pound of fudge = $2.30

Let the amount of fudge be p

We need to find the amount of Money Maggie has left with after visiting the store.

The amount of Money Maggie has left with can be calculate by subtracting the amount of fudge she bought multiplied by Cost of 1 pound of fudge with Money Maggie brought at store.

The equation can be framed as;

Money left = 10-2.3p

Hence, The expression that represent the money Maggie has left after visiting the candy store is (10-2.3p)

3 0
2 years ago
Michaela’s class used a spinner that has 6 spaces of equal area in which the arrow can land. The areas are numbered 1, 2, 3, 4,
diamong [38]

The number of times the spinner landed on a space numbered greater than 4 = 167

Step-by-step explanation:

Step 1 :

Given,

Number of equal area spaces in the spinner = 6

Number of times the spinner was spun = 500

We need to find  the number of times the spinner landed on a space numbered greater than 4

Step 2 :

Total number of outcome = 6

Favorable outcomes are = Numbers greater than 4 = 5,6

Total number of favorable outcome = 2

Therefore Probability that the spinner will land on a number that is greater than 4 is \frac{2}{6} = \frac{1}{3}

The number of times that the spinner landed on a space numbered greater than 4 = 500 × \frac{1}{3} = 166.67 = 167 (rounded off to the nearest integer)

Step 3 :

Answer :

The number of times the spinner landed on a space numbered greater than 4 = 167

4 0
2 years ago
Bradley is returning home from a place that is 2 kilometers away. The function y = 2,000 − 90x represents Bradley's distance fro
Elena-2011 [213]
In an algebraic equation, you should have at least 2 variables: the independent and the dependent. The independent variable in this case, is the parameter that cannot be controlled - time. This is expressed in minutes using the variable x. The dependent variable is the parameter you want to measure - the distance expressed using the variable y. Since the problem states a parameter of distance in terms of 2 kilometers, y=2. Therefore, I think the choices would be about the amount of minutes it would take for Bradley to cover this distance. Assuming this is the case, then the answer would be:
 
2 = 2000 - 90x
90x = 2000-2
90x = 1998
x = 1998/90
x = 22.3 minutes
 
It would take 22.3 minutes for Bradley to cover the 2 kilometers so that he could get home.
4 0
2 years ago
The number of milligrams of a certain medicine a veterinarian gives to a dog varies directly with the weight of the dog. If the
Andre45 [30]

Answer:

Step-by-step explanation:

A direct variation equation is of the form

y = kx,

where, in words, it reads "y varies directly with x" or "y varies directly as x". In order to use this as a model, we have to have enough information to solve for k, the constant of variation. The constant of variation is kind of like the slope in a straight line. It rises or falls at a steady level; it is the rate of change.

We have that a vet gives a dose of three-fifths mg to a 30 pound dog. If the dose varies directly with the weight of the dog, then our equation is

d = kw and we need to find k in order to have the model for dosing the animals.

\frac{3}{5} =k(30)

Divide both sides by 1/30 to get k alone.

(\frac{1}{30})(\frac{3}{5})=k and

k=\frac{1}{50}

Our model then is

d=\frac{1}{50}w

This means that for every pound of weight, the dog will get one-fiftieth of a mg of medicine.

7 0
2 years ago
Read 2 more answers
Determine a series of transformations that would map polygon ABCDE onto<br>polygon A'B'C'D'E'?<br>​
vovangra [49]

Answer:

A reflection followed by a translation

Step-by-step explanation:

A reflection across they x-axis would put all the points in the right section and on the right y value. The x value would need to be changed though. So, you would need to do a translation of 4 on all points.

3 0
2 years ago
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