Answer:
x = 6 ft
Step-by-step explanation:
Total area of the given polygon = Area of triangle 1 + Area of rectangle 2 + Area of triangle 3
Area of triangle 1 = Area of triangle 3 = 
= 
= 4x square feet
Area of rectangle 2 = Length × Width
= 16 × 8
= 128 square feet
Total area of the given polygon = 4x + 128 + 4x
176 = 8x + 128
8x = 176 - 128
x = 
x = 6 ft
Question says that "Last week, Jason ran 26.1 miles. He wants to run further this week. He plans to run 2.4 miles to the park, four times around the park, and 2.4 miles back from the park. To represent that inequality, he wrote: 2.4 + 4p + 2.4 ___ 26.1"
We see a blank space before 26.1.
So we need to fill the suitable inequality symbol from <, >, ≤ and ≥.
In given expression "2.4 + 4p + 2.4 ___ 26.1", left side part "2.4 + 4p + 2.4", represents the total length of the path that Jason wants to cover this week.
He has decided to run more than 26.1 miles so that means the sum "2.4 + 4p + 2.4" must be greater than 26.1 miles.
Hence we will use > symbol so that left side becomes greater than the right side part.
So the final answer will be :
2.4 + 4p + 2.4 > 26.1
Answer:
210.6 cm
Step-by-step explanation:
Given that a piece of ribbon is cut into two shorter pieces in the ratio 2.8:1.25.
So that means length of the first smaller piece = 2.8x
and length of the second smaller piece = 1.25x
Then difference between their lengths = 2.8x-1.25x = 1.55x
Given that difference is equal to 80.6 centimeters then we get
1.55x=80.6
or x= 80.6/1.55
or x=52
then length of the original piece = 2.8x+1.25x
= 2.8*52+1.25*52
= 145.6+65
= 210.6 cm
Question:
Aubrey has a new art box in the shape of a rectangular prism. The box is 5 inches by 8 inches by 2 inches. The only thing in the art box is a new pink eraser with the dimensions shown below.
0.25 inches by 1 inches by 2 in
ches
What is the volume of the art box not taken up by the eraser?
Answer:
Step-by-step explanation:
Given
Volume is calculated as:
First, we calculate the volume of the box:
Next, we calculate the volume of the eraser.
The volume not taken up is calculated as thus:
