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Ivan
2 years ago
9

Please help. Find the length of the side labeled x. Round intermediate values ​​to the nearest thousandth. Use the rounded value

s ​​to value. Round your final answer to the nearest tenth

Mathematics
2 answers:
Vaselesa [24]2 years ago
5 0
19)18.7 20)7.9
21)13.3 22)102.4
gogolik [260]2 years ago
4 0

Answer:

18.692

48.344

7.075

101.972

Step-by-step explanation:

19)

cos23=\frac{BD}{AB}\\\Rightarrow BD=cos23\times 29

tan 55=\frac{BD}{DC}\\\Rightarrow tan 55=\frac{cos23\times 29}{x}\\\Rightarrow x=\frac{cos23\times 29}{tan55}\\\Rightarrow x=18.692

x = 18.692

20)

tan68=\frac{AD}{BD}\\\Righarrow tan68=\frac{16}{BD}\\\Rightarrow BD=\frac{16}{tan68}

cos35=\frac{BD}{BC}\\\Rightarrow cos35=\frac{\frac{16}{tan68}}{x}\\\Rightarrow x=\frac{\frac{16}{tan68}}{cos35}\\\Rightarrow x=48.344

x = 48.344

21)

cos62=\frac{BD}{AB}\\\Rightarrow cos62=\frac{BD}{20}\\\Rightarrow BD=20\times cos62

tan 37=\frac{DC}{BD}\\\Rightarrow tan 37=\frac{x}{20\times cos62}\\\Rightarrow x=tan37\times 20\times cos62\\\Rightarrow x=7.075

x = 7.075

22)

tan24=\frac{AD}{BD}\\\Rightarrow tan24=\frac{47}{BD}\\\Rightarrow BD=\frac{47}{tan24}

tan44=\frac{DC}{BD}\\\Rightarrow tan44=\frac{x}{\frac{47}{tan24}}\\\Rightarrow x=tan44\times \frac{47}{tan24}\\\Rightarrow x=101.972

x = 101.972

A, B, C and D have been taken according to the diagram for all the triangles.

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Answer:

a. 205320

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Step-by-step explanation:

a) The number of ways to dustribute exams among the TA's is:

n / (n - r)!

n= number of things to choose from

r= Choosing r number

60P3= 60! / (60 - 3)!

(60)(59)(58)(57)! / (57)!

=205320

B) The number of ways to dustribute the exams among the TA's is:

n! /(n - r)! r!

60C3= 60! /(60 - 3)! 3!

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2 years ago
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As of 12:04 EST U.S.

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8 0
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Answer:

56 number of ways

Step-by-step explanation:

This question is a combination question since it involves selection.

Generally, if r objects are to be selected from n pool of objects, this can be done in nCr number of ways.

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If a manager receives 8 applications for a specific position and wants to narrow it down to 5, the number of ways he can do this is 8C5

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