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1 year ago

WILL MARK BRAINLIEST!!!

Mathematics

2 answers:

Sergeu [11.5K]1 year ago

3 0

Answer:

The answer is the bottom graph on the left. :)

kondor19780726 [428]1 year ago

3 0

Answer:

Bottom left corner.

Step-by-step explanation:

in order to solve this, you just have to evaluate the function when x=0 that means the intersect with Y-axis, so when h(x) = x^3 + 2x^2 - 11x - 12 is evaluated for x=0

y=-12

So the point would be (0,-12)

From the graphs there are two graphs that match this description, now we just have to evaluate the intersect with X, in the bottom left it says that when y=0 x=-4

So we evaluate h(x) = x^3 + 2x^2 - 11x - 12 to x=-4 to see if it equals 0:

$h(x) = x^3 + 2x^2 - 11x - 12\\h(x) = -4^3 + 2(-4)^2 - 11(-4) - 12\\h(x) = -64 +32 +44 - 12\\\\h(x)=0$

As you can see the function equals 0 that means that is the graph of h(x) = x^3 + 2x^2 - 11x - 12

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