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Mrrafil [7]
2 years ago
11

Help please. Find x.

Mathematics
1 answer:
Degger [83]2 years ago
5 0
You have to use the Geometric Mean for triangles to find x.  Our form will look like this: \frac{2}{x} = \frac{x}{6+2} which simplifies to \frac{2}{x} = \frac{x}{8}.  Cross multiply to get x^{2} =16.  Therfore, x = 4.  Usually when we take the square root of a number we will end up with both the principle (positive) root and the negative one as well.  But since the 2 things in math that will never EVER be negative are time and distance/length, we will not consider the -4.  x = 4
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Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 16}{2.1}

Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

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