During the three weeks how many customers came from zones 3 and 4
1 answer:
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Answer:
a) 0.214 = 21.4% probability that at most 4 of the calls involve a fax message
b) 0.118 = 11.8% probability that exactly 4 of the calls involve a fax message
c) 0.904 = 90.4% probability that at least 4 of the calls involve a fax message
d) 0.786 = 78.6% probability that more than 4 of the calls involve a fax message
Step-by-step explanation:
For each call, there are only two possible outcomes. Either it involves a fax message, or it does not. The probability of a call involving a fax message is independent of other calls. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
25% of the incoming calls involve fax messages
This means that
25 incoming calls.
This means that
a. What is the probability that at most 4 of the calls involve a fax message?
.
In which
0.214 = 21.4% probability that at most 4 of the calls involve a fax message
b. What is the probability that exactly 4 of the calls involve a fax message?
0.118 = 11.8% probability that exactly 4 of the calls involve a fax message.
c. What is the probability that at least 4 of the calls involve a fax message?
Either less than 4 calls involve fax messages, or at least 4 do. The sum of the probabilities of these events is 1. So
We want . Then
In which
0.904 = 90.4% probability that at least 4 of the calls involve a fax message.
d. What is the probability that more than 4 of the calls involve a fax message?
Very similar to c.
From a),
Then
0.786 = 78.6% probability that more than 4 of the calls involve a fax message