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2 years ago

14

Between 11 pm and 8:10 am, the water level in a swimming pool decreased by 5/24 inches. Assuming that the water level decreased

at a constant rate, how much did the water level drop each hour?

1 answer:

lapo4ka [179]2 years ago

6 0

Its dropped 7 feet i think im not sure

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Amy is just learning how to rock climb. Her instructor takes her to a 26 ft climbing wall for her first time. She climbs up 5 ft

boyakko [2]

Let's compute the speeds as she goes up and down of the climbing wall. Speed is the ratio of distance to time.

Speed going up = 5 ft/(2min * 60 s/1 min) = 1/24 ft/s
Speed going down = 2 ft/10 s = 0.2 ft/s
Net speed = 1/24 ft/s - 0.2 ft/s = 5/24 ft/s

Using this net speed, we can already calculate for the total time:

Speed = Distance/Time
5/24 ft/s = 26 ft/Time
Time = 124.8 seconds or 2.08 minutes

7 0

2 years ago

A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on

SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

$Z_{1-\alpha /2}= Z_{0.95}= 1.645$

[10.41±1.645* $(\frac{3.71}{\sqrt{28} } )$ ]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0

2 years ago

Sandy has 16 roses,8 daisies, and 32 tulips. She wants to arrange all the flowers in bouguets. Each bouguet has the same number

avanturin [10]

Answer:

Greatest number of flowers that can be used in a bouquet is 8.

Step-by-step explanation:

In this question greatest number of flowers used in a bouquet will be decided by the "Greatest Common Factor" of the numbers of the flowers given.

So, factors of 16 = 1×2×2×2×2

Factors of 8 = 1×2×2×2

Factors of 32 = 1×2×2×2×2×2

Common factors = 1×2×2×2

Greatest Common Factor of these numbers will be = 1×2×2×2 = 8.

Therefore, greatest number of flowers that could be in a bouquet is 8.

3 0

2 years ago

a shopkeeper had purchased 400 products for $40 each the goods did not sell due to quality issues he sold them to a scrap dealer

Ratling [72]

Answer:

6500-40=6460

Step-by-step explanation:

7 0

1 year ago

PLEASE HELP MATH EXPAND LOG

blsea [12.9K]

Answer:

½log3 + ½logx

Step-by-step explanation:

½(log(3x))

½(log3 + logx)

½logx + ½log3

8 0

2 years ago