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kondor19780726 [428]
2 years ago
6

The top surface of a desk has a length of 5.6 ft and the length is 4 times its width what is the width of the desk

Mathematics
1 answer:
IgorLugansk [536]2 years ago
5 0

Answer:

<u>The width of the top surface of the desk is 1.4 feet.</u>

Step-by-step explanation:

1. Let's review all the information given for solving this question:

Length of the top surface of a desk = 5.6 feet

Width of the top surface of a desk= x

2. Let's find the width of the top surface of the desk

Length of the top surface of a desk = Four times the width

5.6 = 4x

5.6/4 = 4x/4 (Dividing by 4 at both sides)

1.4 = x

<u>The width of the top surface of the desk is 1.4 feet.</u>

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Josh has a rewards card for a movie theater. - He receives 15 points for becoming a rewards card holder. - He earns 3.5 points f
jeka94

Answer:

Option A. 3.5x + 15 ≥ 55

Step-by-step explanation:

Points Rosh received for becoming a member = 15

Points Rosh received for visiting the moving theater = 3.5

Total points needed for a free movie ticket = 55

For each visit he receives 3.5 points, so for x visits he will receive 3.5x points.

Total points = Points received on becoming a member + Points received on x visits

So,

Total Points = 15 + 3.5x

These points must be at least 55 for a free movie ticket. At least means equal to or greater than. So the total points must be equal to or greater than 55 in order to earn a free movie ticket. This can be expressed as:

3.5x + 15 ≥ 55

So, option A gives the correct answer

8 0
2 years ago
Read 2 more answers
A player of a video game is confronted with a series of four opponents and an 80% probability of defeating each opponent. Assume
mixer [17]

Answer:

(a) 0.4096

(b) 0.64

(c) 0.7942

Step-by-step explanation:

The probability that the player wins is,

P(W)=0.80

Then the probability that the player losses is,

P(L)=1-P(W)=1-0.80=0.20

The player is playing the video game with 4 different opponents.

It is provided that when the player is defeated by an opponent the game ends.

All the possible ways the player can win is: {L, WL, WWL, WWWL and WWWW)

(a)

The results from all the 4 opponents are independent, i.e. the result of a game played with one opponent is unaffected by the result of the game played with another opponent.

The probability that the player defeats all four opponents in a game is,

P (Player defeats all 4 opponents) = P(W)\times P(W)\times P(W)\times P(W)=[P(W)]^{4} =(0.80)^{4}=0.4096

Thus, the probability that the player defeats all four opponents in a game is 0.4096.

(b)

The probability that the player defeats at least two opponents in a game is,

P (Player defeats at least 2) = 1 - P (Player losses the 1st game) - P (Player losses the 2nd game) = 1-P(L)-P(WL)

                                    =1-(0.20)-(0.80\times0.20)\\=1-0.20-0.16\\=0.64

Thus, the probability that the player defeats at least two opponents in a game is 0.64.

(c)

Let <em>X</em> = number of times the player defeats all 4 opponents.

The probability that the player defeats all four opponents in a game is,

P(WWWW) = 0.4096.

Then the random variable X\sim Bin(n=3, p=0.4096)

The probability distribution of binomial is:

P(X=x)={n\choose x}p^{x} (1-p)^{n-x}

The probability that the player defeats all the 4 opponents at least once is,

P (<em>X</em> ≥ 1) = 1 - P (<em>X</em> < 1)

             = 1 - P (<em>X</em> = 0)

             =1-[{3\choose 0}(0.4096)^{0} (1-0.4096)^{3-0}]\\=1-[1\times1\times (0.5904)^{3}\\=1-0.2058\\=0.7942

Thus, the probability that the player defeats all the 4 opponents at least once is 0.7942.

3 0
2 years ago
In Boston taxicabs charge an initial fare and an additional amount for every mile traveled. Tahira is having trouble figuring ou
nlexa [21]

Answer:

The taxi charges $2.5 for every mile.

Step-by-step explanation:

We are given the following in the question:

Let x be the initial taxicab fare and y be the additional amount for every mile traveled.

Cost for a two mile ride = $7.00

Thus, we can write the equation:

x + 2y = 7

Cost of a nine mile ride = $24.50

Thus, we can write the equation,

x + 9y = 24.50

Solving the two equation by elimination method, we have,

x + 9y - (x + 2y) = 24.50 - 7\\7y = 17.5\\y = 2.5\\\Rightarrow x + 2(2.5) = 7\\x = 2

Thus, $2 is the initial fare and $2.5 is the cost for every mile traveled.

3 0
2 years ago
The center of a hyperbola is located at (0, 0). One focus is located at (0, 5) and its associated directrix is represented by th
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For a hyperbola   \dfrac{y^{2}}{a^{2}}-\dfrac{x^{2}}{b^{2}}=1
where   a^{2}+b^{2}=c^{2}
the directrix is the line   y=\dfrac{a^{2}}{c}
and the focus is at (0, c).

Here, we have c = 5, a² = 9, so b² = 5² - 9 = 16.
  a = √9 = 3
  b = √16 = 4

Your hyperbola's constants are ...
  a = 3
  b = 4


______
Please note that the equation of a hyperbola has a negative sign for one of the terms. The equation given in your problem statement is that of an ellipse.
8 0
2 years ago
Read 2 more answers
A certain organization recommends the use of passwords with the following​ format: vowel commavowel, consonant comma consonant c
zimovet [89]

The password format is = inpray93

vowel , consonant, consonant, consonant, vowel, consonant, number, number.

There are 21 consonants, 5 vowels and 10 number choices (0-9)

Since, there are 21 consonants and repetition is allowed so for 2nd, 3rd, 4th, and 6th positions 21 choices are available. For 1st and 5th positions, 5 choices  are available and for 7th and 8th position there are 10 choices (0 to 9).

Passwords are not case sensitive which means upper case and lower case letters are same.

So, the number of passwords can be =

5\times21\times21\times21\times5\times21\times10\times10

= 486202500

Part (b) question is not given. But it can be opposite to the first part i.e when the password letters are case sensitive.

This means all the letters are different.

So, number of passwords will be =

10\times42\times42\times42\times10\times42\times10\times10

= 31116960000

4 0
2 years ago
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