6 soccer balls for $150

Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the

xenn [34]

Answer:

As per the given statement:

The region bounded by the given curves about the y-axis, $y = 13e^{-x^2}$ , y=0, x = 0 and x = 1

Using cylindrical shell method:

The volume of solid(V) is obtained by rotating about y-axis and the region under the curve y = f(x) from a to b is;

$V = \int_{a}^{b} 2\pi x f(x) dx$ where $0\leq a$

where x is the radius of the cylinder

f(x) is the height of the cylinder.

From the given figure:

radius = x

height(h) =f(x) =y= $13e^{-x^2}$

a = 0 and b = 1

So, the volume V generated by rotating the given region:

$V =2 \pi \int_{0}^{1} x ( 13e^{-x^2}) dx\\\\V=2\pi\left [ -\frac{13}{2}e^{-x^2} \right ]_{0}^{1}\\\\V=2\pi\left (-\frac{13}{2e}-\left(-\frac{13}{2}\right) \right )\\\\V=-\frac{13\pi }{e}+13\pi$

therefore, the volume of V generated by rotating the given region is $V=-\frac{13\pi }{e}+13\pi$

5 0

2 years ago

A total of d dollars was donated to 4 charities. Each charity received $375. Which equation can be solved to find the total amou

lidiya [134]

Answer:

If each charity has received $375 and there is 4 charities, the equation should look like this...

$375 x 4 = d

If you are looking how much was donated all together, the answer is:

$1500 dollars in total was donated.

6 0

2 years ago

The 40th term of the number sequence is 119.<br> (b) Work out the 41st term of the number sequence.

dolphi86 [110]

100000fjwjsnfbc kdjdbf

7 0

1 year ago

(c) if the corresponding terms of two arithmetic sequences are added, is the resulting sequence arithmetic?

Harman [31]

To determine whether the corresponding terms of 2 arithmetic sequence's added will give new arithmetic sequence or not, Let' take 2 Arithmetic sequences.

In one first term is a1 and common difference is d1, in the other first term is a2 and common difference is d2.

Now nth term for first sequence = a1+(n-1) d1

nth term for second sequence = a2+(n-1) d2

Now add the 2 terms: a1+(n-1)d1 +a2 +(n-1)d2

= a1+a2 + (n-1)(d1+d2)

This is again new arithmetic sequence with first term a1+a2 and common difference d1+d2.

Hence if we add corresponding terms of 2 arithmetic sequence, we will again get an arithmetic sequence.

5 0

1 year ago

A sample of the salaries of assistant professors on the business faculty at a local university revealed a mean income of $100,00

serg [7]

Answer:

a) 68%

b) 95%.

c) 2.5%

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 100,000, standard deviation of 10,000.

a. Approximately what percentage of the salaries fall between $90,000 and $110,000?

90,000 = 100,000 - 10,000

110,000 = 100,000 + 10,000

Within 1 standard deviation of the mean, so approximately 68%.

b. Approximately what percentage of the salaries fall between $80,000 and $120,000?

80,000 = 100,000 - 2*10,000

120,000 = 100,000 + 2*10,000

Within 2 standard deviations of the mean, so approximately 95%.

c. Approximately what percentage of the salaries are greater than $120,000?

More than 2 standard deviations above the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean, so approximately 5% are more than 2 standard deviations from the mean.

The normal distribution is symmetric, which means that 2.5% are more then 2 standard deviations below the mean, and 2.5% are more than 2 standard deviations above the mean, which means that 2.5% of the salaries are greater than $120,000.

7 0

2 years ago