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2 years ago

Ten liters of pure water are added to a 50-liter pot of soup that is 50% broth. Fill in the missing parts of the table.

Mathematics

2 answers:

GarryVolchara [31]2 years ago

8 0

Answer:

$c=25$

$d=60$

Step-by-step explanation:

We have been given a table. We are supposed to fill in the missing parts of the table.

$\text{Original amount}+\text{Added}=\text{New}$

$\text{Amount of broth}\Rightarrow25+0$

$\text{Amount of broth}\Rightarrow25$

$c=25$

$\text{Total solution}\Rightarrow50+10$

$\text{Total solution}\Rightarrow60$

$d=60$

Therefore, the value of c is 25 and value of d is 60.

muminat2 years ago

3 0

Answer:

c= 25

d= 60

Step-by-step explanation:

C: This is because 25+0 is 25. You are adding nothing essentially so nothing changes! :)

D: 50 + 10 = 60. Just simple addition!

<h2>Hope this helps!</h2>

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Find the value of the geometric series 1000 + 1000(1.03) + 1000(1.03)2 + . . . + 1000(1.03)9

valentinak56 [21]

Answer:

$\boxed{\sf \ \ \ 11,464 \ \ \ }$

Step-by-step explanation:

hello

we need to compute the following

$\sum\limits^9_{i=0} {1000(1.03)^i}=1000\dfrac{1.03^{10}-1}{1.03-1}=11463.879...$

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4 0

2 years ago

The owners of Prim's Pizza are concerned that many of their customers are starting to purchase pizza from The Pizza Palace becau

AleksandrR [38]

Answer:

$(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953$

$(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047$

And the confidence interval for the difference is between:

$27.953 \leq \mu_1 -\mu_2 \leq 32.047$

Step-by-step explanation:

We have the following info given:

$\bar X_1 = 240$ sample mean for medium Pizzas from Prim's

$\bar X_2 = 210$ sample mean for medium Pizzas from Pizza Place

$s_1 =8.6$ sample deviation for Prim's

$s_2 =5.7$ sample deviation for Pizza Palca

$n_1 =n_2 = 100$ sample size selected for each case

The confidence interval for the difference of means is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

And for the 95% confidence we need a significance level of $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ , the degrees of freedom are given by:

$df= n_1 +n_2 -2= 100+100-2 =98$

And the critical value would be

$t_{\alpha/2}= 1.984$

And replacing we got:

$(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953$

$(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047$

And the confidence interval for the difference is between:

$27.953 \leq \mu_1 -\mu_2 \leq 32.047$

8 0

2 years ago

Polygons ABCD and EFGH are similar. Find the length of EH?

3241004551 [841]

Most likely, polygon ABCD has sides of known lengths.
It is also likely that one of the sides of polygon EFGH (not EH) is also known. For instance, its side EF.

If the above is true, we can find the scaling factor as a ratio between lengths of corresponding sides:
r=EFAB

Since this ratio is constant for any two corresponding lengths,
r=EHAD

From the last two equations we can derive:
EH=AD⋅EFAB

Hope That Helped : ) (Took a minute)

5 0

2 years ago

How do the graphs of the functions f(x) = (3/2)^x and g(x) = (2/3)^x compare?

Pani-rosa [81]

Sample Response: The graphs are reflections of each other over the y-axis. The graph of g(x) shoes exponential decay, while the graph of f(x) shows exponential growth.

6 0

2 years ago

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Solve for x 3x−91>−87 OR 21x−17>25

klasskru [66]

Answer:

x > 4/3

Step-by-step explanation:

The first inequality can be solved this way ...

3x -91 > -87

3x > 4 . . . . . . . add 91

x > 4/3 . . . . . . divide by 3

The second inequality has solution ...

21x -17 > 25

21x > 42 . . . . . . add 17

x > 2 . . . . . . . . . divide by 21

The solution set is the union of these overlapping solutions, so will be equal to the first solution:

x > 4/3

5 0

2 years ago

Read 2 more answers