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alukav5142 [94]
2 years ago
14

Steve is trying to increase his average pace per mile by running hills. The hill on 1st Avenue rises 3 vertical feet for each ho

rizontal foot. The hill on 16th Avenue rises 1 vertical foot for every 3 horizontal feet.
Which hill will be more difficult for Steve to run up? Explain your reasoning.

Mathematics
2 answers:
marissa [1.9K]2 years ago
7 0
1st Avenue would be more difficult because it’s rise and run is for every one foot forward it is 3 feet up. Meanwhile avenue 16th would start at (3,1) and the rise and run would be for every 3 feet it would go up 1 foot.
Liula [17]2 years ago
7 0

Answer:

The first Avenue will be more difficult  for Steve to run up.

Step-by-step explanation:

Before to get started, please take a look  at the attached sketch below.

Take in account that slope is a number that describes the steepness of a line. It  can be computed   through the ratio of the vertical change to the horizontal change.

According to this, the slope of the first avenue is 3/1 and the slope of the 16th avenue is 1/3. Therefore, the first avenue inclination is greater than 16 th avenue. This means that the first avenue requires  more effort  to be run up.

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Answer:

q = -6p + 104

Step-by-step explanation:

Linear function:

A linear function has the following format:

q = mp + b

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This means that we have these following points: (4,80), (10,44).

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With a pair of points, the slope is given by the change in q divided by the change in p.

Change in q: 44 - 80 = -36

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2 years ago
Two cells are viewed and measured under a microscope. The approximate diameter
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Answer:

option D. 4.7 x 10-4 m

Step-by-step explanation:

<u><em>The correct question is</em></u>

• cell P: 5.0 x 10-4 meters

• cell Q: 3.0 x 10-5 meters

we have            

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The diameter of cell Q is  3*10^{-5}\ m

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Rewrite the difference as

47*10^{-5}\ m=47*10^{-5}}(\frac{10}{10})=4.7*10^{-4}\ m

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