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1 year ago

Which decimal number is equal to 3/18 ? 0.167 0.16 0.16 0.167

Mathematics

2 answers:

Anuta_ua [19.1K]1 year ago

8 0

Answer:

b the one with the shorter line or shortest line like this -- not -------- or -------

Step-by-step explanation:

im in 7th grade and took the quiz and got b

Rus_ich [418]1 year ago

5 0

3/18 = 1/6 =.16666666.....

.16(repeating)

your choice A and D are the same

and choice B and C are the same

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Use the drawing tool(s) to form the correct answers on the provided graph.

anastassius [24]

Answer:

See below in bold.

Step-by-step explanation:

This is the vertex form of a parabola which opens upwards.

To find the x intercept put h(x) = 0:

(x + 1)^2 - 4 = 0

(x + 1)^2 = 4

x + 1 = +/- 2

x = (-3, 0) an (1, 0) are the x-intercepts.

For the y-intercept we put x = 0

y = (0+1)^2 - 4 = -3

y-intercept = (0, -3).

The vertex is (-1, -4).

Axis of symmetry is x = -1.

4 0

1 year ago

Read 2 more answers

According to a survey, 10% of Americans are afraid to fly. Suppose 1100 Americans are sampled. a) What is the probability that 1

JulijaS [17]

Answer:

a) 14.46%

b) 0.00%

c) 1.54%

Step-by-step explanation:

According to the survey, 10% of Americans are afraid to fly.

This means $p=0.10$ and $q=1-0.10=0.90$ .

If 1100 Americans are sampled, then the sample size is $n=1100$ .

The mean of the distribution is $\mu=np$ .

This means $\mu=1100\times 0.10=110$

The standard deviation is $\sigma=\sqrt{npq}$

We substitute the values to get:

$\sigma=\sqrt{1100\times 0.1\times 0.9}=9.95$

a) We want to find the probability that 121 or more Americans in the survey are afraid to fly.

We first apply the continuity correction factor to get: $P(X\ge121)=P(X\:>\:121-0.5)\\P(X\ge121)=P(X\:>\:120.5)$

We now convert to Z-scores to get:

$P(X\:>\:120.5)=P(z\:>\:\frac{120.5-110}{9.95})=1.06\\$

From the standard normal distribution table P(z>1.06)=0.1446

As a percentage, the probability is 14.46%

b) We want to find the probability that 165 or more Americans in the survey are afraid to fly.

We apply the CCF to get:

$P(X\ge165)=P(X\:>\:165-0.5)\\P(X\ge165)=P(X\:>\:164.5)$

We convert to z-scores:

$P(X\:>\:164.5)=P(z\:>\:\frac{164.5-110}{9.95})=5.48$

From the normal distribution, P(z>164.5)=0

c) First, 8% of 1100 is 88.

We want to find the probability that 88 or less Americans in the survey are afraid to fly.

We apply the CCF to get:

$P(X\le88)=P(X\:$

We convert to z-scores:

$P(X\:$

From the normal distribution, P(z>\:-2.16)=0.0154

As a percentage, we get 1.54%

3 0

2 years ago

Find the area of triangle ABC.

elena-14-01-66 [18.8K]

Answer:

24 centimetre

hope it is helpful

4 0

1 year ago

Harry's Electronics kept track of how many customers bought a newly released gaming system during the first month it was availab

lukranit [14]

More description not a valid question.

6 0

2 years ago

A sample with a sample proportion of 0.4 and which of the following sizes will produce the widest 95% confidence interval when e

Fed [463]

Answer:

C. 50

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

The higher the margin of error, the wider an interval is.

As the sample size increases, the margin of error decreases. If we want a widest possible interval, we should select the smallest possible confidence interval.

So the correct answer is:

C. 50

6 0

2 years ago