The cost to rent the canoe for 7 hours is $ 104
<em><u>Solution:</u></em>
At eagle bay it cost $12 per hour to rent a Canoe
Nate and his friends rented a canoe for 4 hours and paid $68
Let "x" be the number of hours rented
We can solve use the point slope equation
Where, "m" is the rate of change
is the sample point
From given,
m = 12
Therefore,
Thus the linear equation is found
Here, "y" represents the amount paid for "x" hours
<em><u>Find the cost to rent the canoe for 7 hours</u></em>
Substitute x = 7 in linear equation
y = 12(7) + 20
y = 84 + 20
y = 104
Thus cost to rent the canoe for 7 hours is $ 104
Answer:
D sentence 5
Step-by-step explanation:
For a 30-60-90 triangle the sides always have the same relationship
Short leg = a
Long leg = a√3
Hypotenuse = 2a
BC is the short leg of ∆ABC
Given BC = 2
BC = a
Therefor
a = 2
AB = 2a = 4
AC = a√3 = 2√3
For ∆ACD
As above AC = 2√3
Since AC is the hypotenuse of ∆ACD
2a = 2√3
a = √3
CD = a = √3
AD = a√3 = 3
For ∆BCD
As above
BC = 2
CD = √3
Since BC is the hypotenuse of ∆BCD
2a = 2
a = 1
DB = a = 1
Answer:
765 J
Step-by-step explanation:
We are given;
Mass of bucket = 30 kg
Mass of rope = 0.3 kg/m
height of building= 30 meter
Now,
work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand
Or W = W1 + W2
Work done in lifting the rope is given as,
W1 = Force x displacement
W1 = (30,0)∫(0.2x .dx)
Integrating, we have;
W1 = [0.2x²/2] at boundary of 30 and 0
W1 = 0.1(30²)
W1 = 90 J
work done in lifting the sand is given as;
W2 = (30,0)∫(F .dx)
F = mx + c
Where, c = 30 - 15 = 15
m = (30 - 15)/(30 - 0)
m = 15/30 = 0.5
So,
F = 0.5x + 15
Thus,
W2 = (30,0)∫(0.5x + 15 .dx)
Integrating, we have;
W2 = (0.5x²/2) + 15x at boundary of 30 and 0
So,
W2 = (0.5 × 30²)/2) + 15(30)
W2 = 225 + 450
W2 = 675 J
Therefore,
work done lifting the bucket (sand and rope) to the top of the building,
W = 90 + 675
W = 765 J
Answer:
a. the probability that any one of the computers will require repair on a given day is constant
Step-by-step explanation:
The following properties must be true in order for a distribution to be binomial:
- A fixed number of trials (125 computers)
- Each trial is independent of the others (one computer requiring repair does not interfere with the likelihood of another requiring repair).
There are only two outcomes (requires repair or do not require repair)
The probability of each outcome remains constant from trial to trial (All computers have the same likelihood of requiring repair, 0.15).
Therefore, the alternative that better fits those properties is alternative a. the probability that any one of the computers will require repair on a given day is constant
