Length=2x
width=x
Perimeter of a rectangle=2(lenght)+2(width)
The first is to find out the measures of this rectangle, that is to say, you have to find the length and width of these rectangle.
We can suggest this equation:
24=2(2x)+2(x)
4x+2x=24
6x=24
x=24/6
x=4
2x=2(4)=8
The lenght will be 8 in, and the length will be 4 in.
The second; you have to calculate the area of this rectangle.
area of a rectangle= lenght x width
area=(8 in)(4 in)=32 in²
answer: the area of Marshall´s rectangular poster would be 32 in²
Answer:
x=10.25
Step-by-step explanation:
If the two angles are congruent, then the measures are equivalent. Therefore, we can set the measures equal to each other and solve for x.
5x+24=9x-17
We want to find out what x is. In order to do this, we have to get x by itself. Perform the opposite of what is being done to the equation. Keep in mind, everything done to one side, has to be done to the other.
First, subtrct 5x from both sides.
5x-5x+24=9x-5x-17
24=9x-5x-17
24=4x-17
Next, add 17 to both sides.
24+17=4x-17+17
24+17=4x
41=4x
Lastly, divide both sides by 4, since 4 and x are being multiplied (4*x=4x).
41/4=4x/4
41/4=x
10.25=x
If the angles are congruent, then the value of x is 10.25.
Answer:
a) The function is constantly increasing and is never decreasing
b) There is no local maximum or local minimum.
Step-by-step explanation:
To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.
f(x) = ln(x^4 + 27)
f'(x) = 1/(x^2 + 27)
Now we take the derivative and solve for zero to find the local max and mins.
f'(x) = 1/(x^2 + 27)
0 = 1/(x^2 + 27)
Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.
Answer:
D
Step-by-step explanation:
Because 150 times 4 = 600.
