Answer:
The measure of Arc EH is 123°.
Step-by-step explanation:
Consider the diagram below.
It is provided that ∠EDH ≅ ∠EDG.
This implies that: ∠EDH = ∠EDG
The arc measure is same as the measure of the central angle.
That is:
arc FE = ∠EDF = 57°
arc FG = ∠FDG = 66°
Compute the measure of angle ∠EDH as follows:
arc EH = ∠EDH
=∠EDG
= ∠EDF + ∠FDG
= 57° + 66°
= 123°
Thus, the measure of Arc EH is 123°.
Answer in simplified expression: 5a+4
Hey there!
Before you start solving anything, you need to identify which situation you want to call event A and which you want to call event B. I usually just do it in the order of the events as they're given to me in the question, so:
A = S<span>tudent participates in student council
B = S</span><span>tudent participates in after school sports
Any problems that contain the word "given" in the question portion will want you to refer to </span>P(A | B)<span> = P(</span>A ∩ B)/P(B). P(A | B) literally means "probability of event A, given that event B has occurred." P(A ∩ B) is the probability of event A and B happening, and P(B) is just the probability of event B happening. We've been given all of that, so:
P(A | B) = P(A ∩ B)/P(B)
P(A | B) = 11% / 62%
P(A | B) = 0.11 / 0.62
P(A | B) = 0.18
There will be about an 18% chance that <span>a student participates in student council, given that the student participates in after school sports.
Hope this helped you out! :-)</span>
we know that
The measurement of <u>the external angle</u> is the semi-difference of the arcs it includes.
In this problem
![21\°=\frac{1}{2}[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=21%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20RU-arc%5C%20SU%5D)
Solve for the measure of arc SU
![42\°=[arc\ RU-arc\ SU]](https://tex.z-dn.net/?f=42%5C%C2%B0%3D%5Barc%5C%20RU-arc%5C%20SU%5D)
therefore
the answer is
The measure of the arc SU is 
We have to determine which value is equivalent to | f ( i ) | if the function is: f ( x ) = 1 - x. We know that for the complex number: z = a + b i , the absolute value is: | z | = sqrt( a^2 + b^2 ). In this case: | f ( i )| = | 1 - i |. So: a = 1, b = - 1. | f ( i ) | = sqrt ( 1^2 + ( - 1 )^2) = sqrt ( 1 + 1 ) = sqrt ( 2 ). Answer: <span>C. sqrt( 2 )</span>
