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galina1969 [7]
2 years ago
8

On which of these policies will an insurer pay if there’s a loss

Mathematics
1 answer:
Ierofanga [76]2 years ago
5 0

Answer:

Fire & Auto

Step-by-step explanation:

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Money Spent on Road Repair A politician wishes to compare the variances of the amount of money spent for road repair in two diff
Mkey [24]

Answer:

(A) Null Hypothesis, H_0 : \sigma_1^{2} =\sigma_2^{2}      {means that there is no significant difference in the variances of the amounts spent in the two counties}

Alternate Hypothesis, H_A : \sigma_1^{2} \neq \sigma_2^{2}      {means that there is a significant difference in the variances of the amounts spent in the two counties}

(B) The F-table gives critical values of 0.359 and 2.781 for (14,17) degrees of freedom for the two-tailed test.

(C) The value of the F-test statistic is 0.611.

(D) We conclude that there is no significant difference in the variances of the amounts spent in the two counties.

Step-by-step explanation:

We are given that a politician wishes to compare the variances of the amount of money spent on road repair in two different counties.

The data are given here below;

County A              County B

s1 = $11,596         s2 = $14,837

n1 = 15                     n2 = 18

Let \sigma_1^{2} = variances of the amounts spent in County A.

\sigma_2^{2} = variances of the amounts spent in County B.

(A) So, Null Hypothesis, H_0 : \sigma_1^{2} =\sigma_2^{2}      {means that there is no significant difference in the variances of the amounts spent in the two counties}

Alternate Hypothesis, H_A : \sigma_1^{2} \neq \sigma_2^{2}      {means that there is a significant difference in the variances of the amounts spent in the two counties}

The test statistics that would be used here <u>Two-sample F-test statistics </u>distribution;

                             T.S. =  \frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }  ~ F__n_1_-_1,_ n_2_-_1

where, s_1 = sample standard deviation for County A = $11,596

s_2 = sample standard deviation for County B = $14,837

n_1 = sample size for County A = 15

n_2 =  sample size for County B = 18

(B) Now at 0.05 level of significance, the F-table gives critical values of 0.359 and 2.781 for (14,17) degrees of freedom for the two-tailed test.

(C) So, <u><em>the test statistics</em></u>  =  \frac{11,596^{2}  }{14,837^{2} } \times 1  ~  F__1_4,_ 1_7

                                     =  0.611

The value of the F-test statistic is 0.611.

Now, as we can see that our test statistics lie within the range of critical values of F, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

(D) Therefore, we conclude that there is no significant difference in the variances of the amounts spent in the two counties.

7 0
2 years ago
Victoria read a 160-page historical fiction novel followed by a science fiction novel of the exact same length. Her average read
postnew [5]

The answer is C: the average reading speed of the science fiction novel.

If x is her reading speed for the historical fiction novel, and her reading speed for the sci-fi novel is just two pages more than that of the historical fiction novel, then the equation to find out how fast she reads the science fiction novel would be x + 2, as you’re adding 2 to the reading speed of the historical fiction book (x)

6 0
2 years ago
Read 2 more answers
Charlie bought a pair of shorts at the store when they were having a 45% off sale. If the regular price of the pair of shorts wa
spayn [35]

Answer:

$13.20

Step-by-step explanation:

5 0
2 years ago
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In the diagram below AB is parallel to CD what is the value of y
Mashutka [201]

Answer:

y=60 due to adjacent angle

5 0
2 years ago
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How much heat is required to raise the temperature of
Elina [12.6K]

Answer:

The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .

Step-by-step explanation:

Given as :

The mass of liquid water = 50 g

The initial temperature = T_1 = 15°c

The final temperature = T_2  = 100°c

The latent heat of vaporization of water = 2260.0 J/g

Let The amount of heat required to raise temperature = Q Joule

Now, From method

Heat = mass × latent heat × change in temperature

Or, Q = m × s × ΔT

or, Q =  m × s × ( T_2 - T_1 )

So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )

Or, Q =  50 g × 2260.0 J/g × 85°c

∴   Q = 9,605,000  joule

Or, Q =  9,605 × 10³ joule

Or, Q = 9605 kilo joule

Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer

4 0
2 years ago
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