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IrinaVladis [17]
2 years ago
9

Find the average value of the function f(x, y, z) = 5x2z 5y2z over the region enclosed by the paraboloid z = 4 − x2 − y2 and the

plane z = 0.
Mathematics
1 answer:
S_A_V [24]2 years ago
3 0
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin. 

<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>

<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>

<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>

<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>


<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>

<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>

<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>

<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>

<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
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Step-by-step explanation:

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Suppose that the probability density function for the length x in feet of some type of fish caught by sport fishermen is given b
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The probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is 0.4375.

Step-by-step explanation:

The probability density function or p.d.f. for the length <em>x,</em> in feet, of some type of fish caught by sport fishermen is :

p(x) = \left \{{{(\frac{1}{4})\ ;\  0\leq x\leq 4 } \atop{0\ ;\ otherwise} \right.

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P(0.25\leq X\leq 2)=\int\limits^{0.25}_{2} {(\frac{1}{4})} \, dx \\=|(\frac{1}{4})x|^{2}_{0.25}\\=(\frac{1}{4})(2-0.25)\\=0.4375

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2 years ago
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How much water do you add  to make 12% sugar syrup using 5g sugar?
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so the syrup is just water and sugar, we know that the sugar percent is just 12%, and that happens to be 5grams.

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2 years ago
Read 2 more answers
The data below shows the heights in inches of 10 students in a class. StudentHeight, in inches Student 153 Student 252.5 Student
Marianna [84]

Question not correct, so i have attached the correct question.

Answer:

SE = 0.59

Step-by-step explanation:

The mean of the students height is;

x' = (53 + 52.5 + 54 + 51 + 50.5 + 49.5 + 48 + 53 + 52 + 50)/10

x' = 51.35

Now, deviation from the mean for each height;

53 - 51.35 = 1.65

52.5 - 51.35 = 1.15

54 - 51.35 = 2.65

51 - 51.35 = -0.35

50.5 - 51.35 = -0.85

49.5 - 51.35 = -1.85

48 - 51.35 = -3.35

53 - 51.35 = 1.65

52 - 51.35 = 0.65

50 - 51.35 = -1.35

Now, square of the deviations above;

1.65² = 2.7225

1.15² = 1.3225

2.65² = 7.0225

-0.35² = 0.1225

-0.85² = 0.7225

-1.85² = 3.4225

-3.35² = 11.2225

1.65² = 2.7225

0.65² = 0.4225

-1.35² = 1.8225

Sum of the squared deviations;

2.7225 + 1.3225 + 7.0225 + 0.1225 + 0.7225 + 3.4225 + 11.2225 + 2.7225 + 0.4225 + 1.8225 = 31.525

Let's divide the sum by the DF of n - 1 i.e 10 - 1 = 9.

Thus;

31.525/9 = 3.50278

Taking the square root of that gives us the standard deviation.

Thus;

s = √3.50278

s = 1.8716

Formula for standard error is;

SE = s/√n

SE = 1.8716/√10

SE = 0.59

8 0
2 years ago
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