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ASHA 777 [7]
2 years ago
9

Hilda was simplifying some numerical expressions and made each of the following sequences of calculations. Name the mathematical

property, operation, or idea that justifies how Hilda went from each step to the next step, some of the steps are done for you. Look at the Math Notes found on page 190 for definitions. Problem
Problem 1: 5 · (−4/3) · (2/5)
= (−4/3) · 5 · (2/5)
= (−4/3) · (5 · (2/5))
= (−4/3) · (2/1) = −8/3 = −2*2/3
Problem 2: 17 + 29 + 3+ 1
= 17 + 3 + 29 + 1
= (17 + 3) + (29 + 1)
= 20 + 30 Added groups
= 50 Added terms
Mathematics
2 answers:
Galina-37 [17]2 years ago
4 0

Answer:

Problem 1:

5 · (−4/3) · (2/5)

= (−4/3) · 5 · (2/5)   <em>Conmutative Property of Multiplication</em>

= (−4/3) · (5 · (2/5))  <em>Associative Property of Multiplication</em>

= (−4/3) · (2/1) = −8/3 = −2*2/3<em> Multiplied fractions and extracted common factor</em>

Problem 2:

17 + 29 + 3+ 1

= 17 + 3 + 29 + 1  <em>Conmutative Property of Addition</em>

= (17 + 3) + (29 + 1)  <em>Associative Property of Addition</em>

= 20 + 30 Added groups

= 50 Added terms

Step-by-step explanation:

<u>For the Problem 1:</u>

In the first step, Hilda applied the <em>Conmutative Property of Multiplication</em>, because she changed the order of the numbers in the product

In the second step, she applied the <em>Associative Property of Multiplication, </em>because she agrouped the product of 5 and<em> </em>2/5 to perform it sepparately

In the third step, she calculated<em> the product of the fractions</em> -4/3 and 2/1, then she extracted 2 as a <em>common factor</em> to express the fraction as -2*2/3

<u>For the Problem 2:</u>

In the first step, Hilda applied the <em>Conmutative Property of Addition, </em>because she changed the order of the numbers in the sum

In the second step, she applied the<em> Associative Property of Addition, </em>because she associated the addition of 17 and 3 and the addition of 29 and 1, to calculate them in groups.

<em />

erica [24]2 years ago
3 0

Answer:

The reason for each statement is shown below.

Step-by-step explanation:

Commutative Property of Multiplication:

a\times b=b\times a

Associative Property of Multiplication:

a\times (b\times c)=(a\times b)\times c

Commutative Property of Addition:

a+b=b+a

Associative Property of Addition:

a+(b+c)=(a+b)+c

Problem 1:

The given expression is

5\cdot (-\frac{4}{3})\cdot(\frac{2}{5})

It can be written as

[5\cdot (-\frac{4}{3})]\cdot(\frac{2}{5})

[(-\frac{4}{3})\cdot 5]\cdot (\frac{2}{5})          (Commutative Property of Multiplication)

(-\frac{4}{3})\cdot [5\cdot (\frac{2}{5})]        (Associative Property of Multiplication)

(-\frac{4}{3})\cdot \frac{2}{1}=-\frac{8}{3}=-2\frac{2}{3}        (Simplification)

Problem 2:

The given expression is

17 + 29 + 3+ 1

It can written as

17 + (29 + 3)+ 1

17 + (3+29)+ 1         (Commutative Property of Addition)

(17 +3)+(29+ 1)        (Associative Property of Addition)

20+30          (Added groups)

50          (Added terms)

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Question is Incomplete; Complete question is given below;

What is the completely factored form of 3x5 – 7x4 + 6x2 – 14x.

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The Complete factorized form of given equation is x((x^3+2)(3x-7)).

Step-by-step explanation:

Given:

3x^5-7x^4+6x^2-14x

We need to factorize the above equation:

Solution:

On Solving the above equation we get;

Step 1:

First we will take a common factor which is 'x' so the equation will become as;

x(3x^4-7x^3+6x-14)

Step 2:

Now we will Rewrite the above equation so as to factorize the same we get;

x(3x^4+6x-7x^3-14)

Step 3:

Now we take 3x common factor from first 2 terms we get;

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Step 4:

Now we will take 7 as common factor from last 2 terms we get;

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Step 5:

Now we can see the common factor between the 2 terms is x^3+2;

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